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Since E=4, and we need A on 5,6, or 7, let's test each case
4
From 'C immediately below D', they occupy consecutive floors
5
'F above G but below C' means G < F < C < D (consecutive)
6
Testing B=2, A=5, E=4: Remaining floors 1,3,6,7 for C,D,F,G
7
If C=6, D=7, then F<6, so F could be 3, G could be 1
Final Answer: G=1, B=2, F=3, E=4, A=5, C=6, D=7
Worked Example 2:
6-floor building, people P,Q,R,S,T,U:
- P lives 2 floors below R
- Q lives on an even-numbered floor
- S lives above T but below Q
- U lives on floor 3
Solution Steps:
2
Q on even floor: 2, 4, or 6
3
P is 2 floors below R: (P=1,R=3), (P=2,R=4), (P=3,R=5), (P=4,R=6)
4
Since U=3, (P=1,R=3) impossible. Test remaining pairs
5
T < S < Q (from condition 3)
6
If P=2, R=4, U=3, Q=6: Remaining floors 1,5 for S,T
7
Since T < S < Q and Q=6, possible: T=1, S=5
Final Answer: T=1, P=2, U=3, R=4, S=5, Q=6
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