Question 1

A 2 kg object accelerates at 3 m/s². What net force acts on it?

Accepted Answer

Using F = ma, F = 2 × 3 = 6 N.

Question 2

An engine does 5000 J of work in 10 seconds. What is its power output?

Accepted Answer

Power = Work / Time = 5000 / 10 = 500 W.

Question 3

A force of 20 N acts on a mass of 4 kg. What is the acceleration produced?

Accepted Answer

Using Newton's second law, F = ma, so a = F/m = 20/4 = 5 m/s².

Question 4

What is the SI unit of force according to Newton's second law of motion?

Accepted Answer

The SI unit of force is Newton (N), defined as 1 kg·m/s² from F = ma.

Question 5

A constant force of 50 N is applied to a 10 kg box on a frictionless surface. If the box starts from rest, what distance does it travel in 4 seconds?

Accepted Answer

First find acceleration: a = F/m = 50/10 = 5 m/s²; then use s = ½at² = ½(5)(4²) = 40 m.

Question 6

A 2 kg object is lifted vertically through a height of 10 m. How much work is done against gravity? (Take g = 10 m/s²)

Accepted Answer

Work against gravity = mgh = 2 × 10 × 10 = 200 J.

Question 7

A particle undergoes uniform circular motion with radius 5 m and completes 2 revolutions in 4 seconds. What is its centripetal acceleration?

Accepted Answer

Angular velocity ω = 2π × (revolutions/time) = 2π × (2/4) = π rad/s; centripetal acceleration = ω²r = π² × 5 = 5π² m/s².

Question 8

A projectile is fired at an angle of 60° with an initial speed of 30 m/s. What is the time of flight? (Take g = 10 m/s²)

Accepted Answer

Time of flight T = (2u sinθ)/g = (2 × 30 × sin60°)/10 = (60 × 0.866)/10 ≈ 5.196 s.

Question 9

A particle travels 60 m in 3 seconds with uniform acceleration starting from rest. What is its final velocity?

Accepted Answer

Using s = (u + v)t/2, where s = 60 m, u = 0, t = 3 s: 60 = (0 + v)×3/2, so v = 40 m/s.

Question 10

A body moving in a straight line has velocity 25 m/s at t = 0 s and velocity 5 m/s at t = 4 s. What is the displacement during this time interval?

Accepted Answer

Using s = (u + v)t/2, where u = 25 m/s, v = 5 m/s, t = 4 s: s = (25 + 5)×4/2 = 60 m.

Question 11

Which of the following correctly defines average velocity for motion in a straight line?

Accepted Answer

Average velocity is the ratio of total displacement to total time; average speed uses distance instead.

Question 12

According to Newton's third law of motion, if object A exerts a force on object B, then:

Accepted Answer

Newton's third law states that forces always occur in equal and opposite pairs between two interacting objects.

Question 13

A uniform rod of mass 2 kg and length 4 m is rotating about its center. If the moment of inertia about the center is 2.67 kg·m², what is the radius of gyration of the rod about its center?

Accepted Answer

Radius of gyration k = √(I/M) = √(2.67/2) = √1.335 ≈ 1.15 m.

Question 14

A force of 20 N is applied to move an object 5 m in the direction of the force. Calculate the work done.

Accepted Answer

Work = Force × Displacement × cos(θ); W = 20 × 5 × cos(0°) = 100 J.

Question 15

A car starts from rest and travels 100 m in 5 seconds with uniform acceleration. What is its acceleration?

Accepted Answer

Using s = ut + ½at², where u = 0, s = 100 m, t = 5 s: 100 = 0 + ½a(25), so a = 8 m/s².

Question 16

A projectile has a range of 40 m on level ground when launched at 45°. If the same projectile is launched at 45° with double the initial velocity, what will be its new range?

Accepted Answer

Range is proportional to u²; doubling u makes range 4 times larger: 40 × 4 = 160 m.

Question 17

An object moving in a straight line has initial velocity 15 m/s and decelerates uniformly at 2 m/s². How long does it take to come to rest?

Accepted Answer

Using v = u + at, where v = 0, u = 15 m/s, a = -2 m/s²: 0 = 15 - 2t, so t = 7.5 s.

Question 18

A projectile is launched at 30° to the horizontal with an initial velocity of 20 m/s. What is the maximum height reached by the projectile? (Take g = 10 m/s²)

Accepted Answer

Maximum height = (u²sin²θ)/(2g) = (400 × sin²30°)/(20) = (400 × 0.25)/20 = 5 m.

Question 19

A stone is thrown horizontally from a cliff with a velocity of 15 m/s. After 2 seconds, what is the vertical component of its velocity? (Take g = 10 m/s²)

Accepted Answer

Vertical velocity at time t: vy = gt = 10 × 2 = 20 m/s (since initial vertical velocity is zero).

Question 20

Which of the following statements correctly defines kinetic energy?

Accepted Answer

Kinetic energy is the energy an object possesses by virtue of its motion; KE = ½mv².

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