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Agniveer Army CEE Speed Distance Time

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This page covers Agniveer Army CEE Speed Distance Time with complete concept notes, 8 graded practice MCQs, key points and exam-specific tips. Free to study.

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Concept Notes

Speed Distance Time— Rules & Concept

Core ConceptRead this first — the foundation of the topic

Speed, Distance, and Time form the foundation of motion problems in SSC CGL. This topic appears in 2-3 questions per exam and requires strong formula application skills. Core Concept: Speed measures how fast an object moves. Distance is the path covered. Time is the duration taken. These three are linked by a simple relationship that forms the base of all calculations.

Formula BlockMemorise — at least one formula appears in every paper
• Speed = Distance/Time (S = D/T)
• Distance = Speed × Time (D = S × T)
• Time = Distance/Speed (T = D/S)

Unit Conversions (Critical for SSC):

• km/hr to m/s: Multiply by 5/18

• m/s to km/hr: Multiply by 18/5

• 1 km/hr = 5/18 m/s
Exam PatternsWhat examiners ask — read before attempting PYQs
Shortcut 1 - Unit Conversion Trick

To convert km/hr to m/s, multiply by 5/18

Remember

36 km/hr = 10 m/s (this is a standard conversion to memorize)

Shortcut 2 - Distance Formula Rearrangement

When speed increases by x%, new time = Original time × 100/(100+x) When speed decreases by x%, new time = Original time × 100/(100-x)

Worked ExampleSolve this step-by-step before moving on
1
Step 1

Find speed in km/hr Speed = Distance/Time = 180/3 = 60 km/hr

2
Step 2

Convert to m/s Speed in m/s = 60 × 5/18 = 300/18 = 16.67 m/s Answer: 16.67 m/s Worked Example 2: A train running at 54 km/hr takes 20 seconds to cross a platform 200m long. Find the length of the train.

1
Step 1

Convert speed to m/s 54 km/hr = 54 × 5/18 = 15 m/s

2
Step 2

Find total distance covered Distance = Speed × Time = 15 × 20 = 300m

3
Step 3

Find train length Train length = Total distance - Platform length = 300 - 200 = 100m Answer: 100 meters Shortcut 3 - Relative Speed: • Same direction: Relative speed = |S1 - S2| • Opposite direction: Relative speed = S1 + S2 Most Common Trap (#1 Mistake): Students forget unit conversions! SSC deliberately mixes km/hr and m/s in the same question. Always check units in options and convert accordingly. Questions asking for train crossing times usually need m/s, while car journey problems often use km/hr. Another frequent error is confusing relative motion directions. When two objects move toward each other, add their speeds. When moving in the same direction, subtract speeds. Time-based problems often trick students with percentage changes in speed. Remember: if speed increases by 25%, time decreases by 20% (not 25%). Use the reciprocal relationship carefully. Practice identifying whether the question asks for train length, crossing time, or platform length. Each requires different approaches but uses the same core formula.

Key Points to Remember

  • Master formula: Speed = Distance/Time and its variations D = S × T and T = D/S
  • Unit conversion: km/hr to m/s multiply by 5/18, m/s to km/hr multiply by 18/5
  • Standard conversion: 36 km/hr = 10 m/s (memorize this)
  • Relative speed: same direction subtract speeds, opposite direction add speeds
  • Train problems: Total distance = Train length + Platform/Bridge length
  • Speed increase by x%: New time = Original time × 100/(100+x)
  • Speed decrease by x%: New time = Original time × 100/(100-x)
  • Always check units in answer options before solving
  • Average speed = Total distance/Total time (not average of individual speeds)
  • Time and speed are inversely proportional when distance is constant

Exam-Specific Tips

  • 1 km/hr equals exactly 5/18 m/s
  • 36 km/hr equals exactly 10 m/s
  • 72 km/hr equals exactly 20 m/s
  • Average speed formula: Total distance divided by total time
  • Relative speed when objects move toward each other: Sum of individual speeds
  • Relative speed when objects move in same direction: Difference of individual speeds
  • When speed increases by 20%, time decreases by 16.67%
  • When speed decreases by 20%, time increases by 25%
Practice MCQs

Speed Distance Time — Practice Questions

8graded MCQs · easy to hard · full solution & trap analysis

All MCQs →
Practice 1easy

A car travels 240 km in 4 hours. What is its average speed?

Practice 2easy

A cyclist travels at a speed of 15 km/h for 3 hours. How much distance does he cover?

Practice 3easy

A boy walks 120 metres at a constant speed of 4 m/s. How much time does he take?

Practice 4medium

A car travels 240 km in 4 hours. What is its average speed?

Practice 5medium

A cyclist travels at 15 km/h for 3 hours. How much distance does he cover?

Practice 6medium

A train covers 360 km at a constant speed of 90 km/h. How long does the journey take?

Practice 7medium

A runner covers 400 m in 50 seconds. What is his speed in m/s?

Practice 8hard

A bus travels 240 km in 4 hours. Due to traffic, it then travels the next 180 km in 5 hours. What is the average speed of the bus for the entire journey?

60-Second Revision — Speed Distance Time

  • Formula: Speed = Distance/Time, Distance = Speed × Time, Time = Distance/Speed
  • Remember: 36 km/hr = 10 m/s for quick conversions
  • Unit conversion: km/hr to m/s multiply by 5/18
  • Trap: Always check if answer needs km/hr or m/s units
  • Relative speed: Add for opposite directions, subtract for same direction
  • Train crossing: Distance = Train length + Platform length
  • Speed-time relationship: Inversely proportional when distance is constant
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