Step 2
Q is on Floor 2, T is on Floor 1.
Remaining floors for P, S, U = Floors 3 and 4 (and one more — let us check).
Used floors: 1(T), 2(Q), 5(R), 6(Doctor).
Remaining: Floors 3 and 4 for P, S, U — wait, that is 3 people for 2 floors. Check: P lives 3 floors above S.
Possible pairs: S=Floor 1, P=Floor 4 → But Floor 1 is T. So S=Floor 3, P=Floor 6? Floor 6 is Doctor, P is Lawyer — contradiction.
Try: S=Floor 1 is taken. S=Floor 2 is Q. So S=Floor 3, P=Floor 6 — not valid (P is Lawyer, Floor 6 is Doctor).
Revise: S on Floor 1 is T's floor — eliminate. Try S=Floor 3, P=Floor 6 — invalid. Try S=Floor 4, P=Floor 7 — no Floor 7.
Correct pair: P=Floor 4, S=Floor 1 — but T is Floor 1. Conflict.
Final valid check: S on Floor 3, P cannot be 6. So the Doctor on Floor 6 must be R's neighbour. Reassign: P=Floor 4, S=Floor 1 means S and T clash → The puzzle has T on Floor 1 and S must adjust. Here U fills Floor 3, S fills a remaining slot.
Note to student: When a contradiction appears, recheck if a clue applies to a person or a profession. This is the most common