1 questions from actual CAPF AC papers · all shown free · click option to reveal solution
Inverse trigonometric functions are the reverse operations of normal trigonometric functions. Think of them as 'undo' buttons. If sin 30° = 1/2, then sin⁻¹(1/2) = 30°. These functions help us find angles when we know the trigonometric ratios. The six inverse trigonometric functions are: sin⁻¹x, cos⁻¹x, tan⁻¹x, cosec⁻¹x, sec⁻¹x, and cot⁻¹x. The notation sin⁻¹x is also written as arcsin x.
Each inverse function has a specific domain and range. For sin⁻¹x: domain is [-1,1] and range is [-π/2, π/2]. For cos⁻¹x: domain is [-1,1] and range is [0, π]. For tan⁻¹x: domain is all real numbers and range is (-π/2, π/2).
NDA papers frequently test inverse trigonometric values of standard angles, domain-range problems, and simplification of expressions. Questions often involve finding exact values like sin⁻¹(√3/2) or solving equations with inverse functions.
For quick calculation, memorize these standard values: sin⁻¹(1/2) = 30°, sin⁻¹(√2/2) = 45°, sin⁻¹(√3/2) = 60°, cos⁻¹(1/2) = 60°, tan⁻¹(1) = 45°, tan⁻¹(√3) = 60°.
Find sin⁻¹(1/2). We know sin 30° = 1/2, so sin⁻¹(1/2) = 30° = π/6
Find cos⁻¹(1/2). We know cos 60° = 1/2, so cos⁻¹(1/2) = 60° = π/3
Add the results: π/6 + π/3 = π/6 + 2π/6 = 3π/6 = π/2 Answer: π/2 Worked Example 2: Simplify: tan⁻¹(1/2) + tan⁻¹(1/3)
Use the formula tan⁻¹x + tan⁻¹y = tan⁻¹[(x+y)/(1-xy)]
Here x = 1/2, y = 1/3
x + y = 1/2 + 1/3 = 3/6 + 2/6 = 5/6
xy = (1/2)(1/3) = 1/6
1 - xy = 1 - 1/6 = 5/6
(x+y)/(1-xy) = (5/6)/(5/6) = 1
tan⁻¹(1) = π/4 = 45° Answer: π/4 Most
Students confuse sin⁻¹x with (sin x)⁻¹ = 1/sin x. Remember: sin⁻¹x means inverse sine function, NOT 1/sin x. The -1 is not an exponent here.
This confusion leads to wrong answers in 40% of student attempts. Always read the notation carefully and understand that sin⁻¹x asks 'which angle has sine equal to x?'
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