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Sets, Relations and Functions form the foundation of modern mathematics and are crucial for NDA exam success. This topic appears in 2-3 questions every year, making it a high-scoring area when mastered properly. CORE CONCEPT
A Set is a collection of distinct objects. A Relation connects elements from one set to another. A Function is a special relation where each input has exactly one output. Think of a function as a machine - you put something in, you get exactly one thing out. **
Set Operations: Union (∪), Intersection (∩), Complement ('), Difference (-) For any sets A and B: n(A∪B) = n(A) + n(B) - n(A∩B) Function Types: One-to-One (Injective), Onto (Surjective), Bijective (both) Domain: Input values, Range: Output values, Codomain: Possible output set
NDA typically asks: Venn diagram problems (40% questions), function domain/range identification (30% questions), relation properties verification (20% questions), and set operation calculations (10% questions). Most questions are direct application based, not proof-based.
** For three sets A, B, C: Draw overlapping circles. Start filling from center (A∩B∩C), then work outward. Use: Only A = n(A) - n(A∩B) - n(A∩C) + n(A∩B∩C).
This eliminates calculation errors. **
Given n(U) = 50, n(C) = 30, n(F) = 25, n(C∩F) = 10
Apply formula n(C∪F) = n(C) + n(F) - n(C∩F)
n(C∪F) = 30 + 25 - 10 = 45
Students playing neither = n(U) - n(C∪F) = 50 - 45 = 5 Answer: 5 students play neither game. WORKED EXAMPLE 2 Find domain of f(x) = √(x-2)/(x-3)
For square root, expression inside must be ≥ 0, so x-2 ≥ 0, giving x ≥ 2
For fraction, denominator cannot be zero, so x-3 ≠ 0, giving x ≠ 3
Combine conditions: x ≥ 2 and x ≠ 3
Domain = [2,3) ∪ (3,∞) Answer: All real numbers greater than or equal to 2, except 3. **
Quick test for function: Draw vertical lines on graph. If any vertical line cuts the curve more than once, it's NOT a function. For one-to-one: use horizontal line test.
** Students confuse 'into' and 'onto' functions. Remember: A function is ONTO when every element in codomain has a pre-image. It's INTO when some codomain elements have no pre-image.
Always check if range equals codomain for onto functions. RELATION PROPERTIES SHORTCUT Reflexive: (a,a) exists for all a Symmetric: If (a,b) exists, then (b,a) exists Transitive: If (a,b) and (b,c) exist, then (a,c) exists Mnemonic: 'RST' - Reflexive Symmetric Transitive makes equivalence relation.
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