1
Find individual rates
A's rate = 1/12 per hour
B's rate = 1/15 per hour
C's rate = -1/20 per hour (negative for outlet)
2
Combined rate = 1/12 + 1/15 - 1/20
3
Take LCM of 12,15,20 = 60
A fills 60/12 = 5 units/hour
B fills 60/15 = 4 units/hour
C empties 60/20 = 3 units/hour
4
Net rate = 5 + 4 - 3 = 6 units/hour
5
Time = 60/6 = 10 hours
Worked Example 2: Two pipes fill tank in 6 hours when opened together. First pipe alone takes 5 hours more than second pipe. Find individual times.
1
Let second pipe take x hours, first takes (x+5) hours
2
Combined rate = 1/6 per hour
4
Cross multiply: 6x + 6(x+5) = x(x+5)
8
(x-10)(x+3) = 0, so x = 10 hours
9
Second pipe = 10 hours, First pipe = 15 hours
Shortcut Trick 1 - Efficiency Method: Instead of fractions, use efficiency. If A completes work in 4 hours and B in 6 hours, their efficiencies are in ratio 6:4 = 3:2. Total work = LCM(4,6) = 12 units