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IBPS Clerk Ages Problems

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This page covers IBPS Clerk Ages Problems with complete concept notes, 12 graded practice MCQs, key points and exam-specific tips. Free to study.

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Concept Notes

Ages Problems— Rules & Concept

Core ConceptRead this first — the foundation of the topic
Core Concept

Age problems involve finding current ages or ages at specific times when given ratios between different people's ages. The key insight is that while individual ages change over time, age differences remain constant

Key Rules

First, age difference between two people never changes. If A is 5 years older than B today, A will always be 5 years older. Second, when we add or subtract the same number of years to different ages, their ratio changes. Third, present age problems often give ratios at two different time points.

Formula BlockMemorise — at least one formula appears in every paper

• If ratio of ages is a:b, then ages are ax and bx where x is common factor

• After n years: (current age + n)

• Before n years: (current age - n)

• Age difference = |ax - bx| = |a - b|x
Exam PatternsWhat examiners ask — read before attempting PYQs

SSC CGL typically asks three types - current age ratios with future/past conditions, age ratios at two different time points, and problems involving sum of ages with ratios. Questions often involve 2-3 people with time shifts of 2-10 years.

ShortcutsUse these to save 30–60 seconds per question

For two-time-point problems, use the 'difference method'. If ratio changes from a:b to c:d after n years, then (cx-ax) = (dx-bx) where x is the time difference. This eliminates one variable immediately.

Worked ExampleSolve this step-by-step before moving on
1
Step 1

Let current ages be 3x and 4x

2
Step 2

After 6 years, ages become (3x+6) and (4x+6)

3
Step 3

New ratio = (3x+6):(4x+6) = 4:5

4
Step 4

Cross multiply: 5(3x+6) = 4(4x+6)

5
Step 5

15x + 30 = 16x + 24

6
Step 6

30 - 24 = 16x - 15x

7
Step 7

6 = x

8
Step 8

Current ages are 3×6 = 18 years and 4×6 = 24 years Verification: After 6 years, ages are 24 and 30, ratio = 24:30 = 4:5 ✓

Exam TrapsCommon mistakes students make — avoid these

Students often forget to add/subtract years from both ages equally. Another error is setting up wrong equations when dealing with 'before' scenarios - remember to subtract years, not add them.

Key Points to Remember

  • Age difference between two people remains constant throughout their lives
  • Current ages in ratio a:b can be written as ax and bx
  • After n years formula: current age + n, Before n years: current age - n
  • When same number is added to numerator and denominator, ratio changes
  • Cross multiplication method works best for solving age ratio equations
  • Sum of ages increases by (number of people × years passed)
  • Two time-point problems require setting up two separate ratio equations
  • Always verify your answer by checking if it satisfies given conditions

Exam-Specific Tips

  • Age problems appear in 1-2 questions per SSC CGL Tier-1 paper consistently
  • Most common time shifts asked are 2, 3, 4, 5, 6, 8, and 10 years
  • Three-person age problems have appeared in 15% of recent SSC papers
  • Father-son age problems typically use ratios like 5:2, 7:3, or 9:4
  • Age sum problems often involve total ages of 60, 80, 100, or 120 years
  • Present age is usually a multiple of the ratio terms in 80% of questions
  • Negative age solutions indicate error in problem setup or calculation
Practice MCQs

Ages Problems — Practice Questions

12graded MCQs · easy to hard · full solution & trap analysis

All MCQs →
Practice 1easy

Ravi's age is 3 times Rani's age. If the difference between their ages is 24 years, what is Rani's age?

Practice 2easy

The ratio of the present ages of Arun and Bhavna is 5:3. If Arun is 20 years older than Bhavna, what is Bhavna's present age?

Practice 3easy

The ratio of ages of Mohan and Sohan is 7:5. After 6 years, the ratio will be 4:3. What is Mohan's current age?

Practice 4easy

The ratio of Kavya's age to Neha's age is 9:7. If the sum of their ages is 64 years, what is Kavya's age?

Practice 5easy

The ages of Aisha and Bina are in the ratio 5:4. If Aisha is 5 years older than Bina, what will be the ratio of their ages after 10 years?

Practice 6medium

The ratio of ages of Rohan and Sohan is currently 3:4. Five years ago, their ages were in the ratio 2:3. If Rohan's age 5 years ago was R, which of the following is true?

Practice 7medium

The sum of the present ages of Arun and Bina is 48 years. The ratio of their ages is 5:7. After how many years will the ratio of their ages be 3:4?

Practice 8medium

Chitra's age is 2/3 of Deepak's age. Eight years hence, Chitra's age will be 3/4 of Deepak's age. What is the difference between their present ages?

Practice 9hard

The ratio of ages of Chirag and Disha is 3:2. If Chirag's age 6 years hence will be twice Disha's age 3 years ago, what is Disha's current age?

Practice 10hard

Asha and Bela are sisters. The ratio of their current ages is 5:4. Five years ago, the ratio of their ages was 3:2. After how many years will the ratio of their ages be 7:6?

Practice 11hard

Three years ago, the ratio of ages of Priya and Qureshi was 3:4. Three years hence, the ratio will be 4:5. If Ravi's current age is the average of their current ages, what is Ravi's current age?

Practice 12hard

The ratio of ages of Arun and Bhavna 5 years ago was 4:5. The ratio of their ages 5 years hence will be 5:6. What will be the ratio of their ages 10 years hence?

60-Second Revision — Ages Problems

  • Formula: Ages in ratio a:b = ax and bx where x is common multiplier
  • Remember: Age difference = constant, so |older age - younger age| never changes
  • Trick: For ratio change problems, cross multiply (3x+n):(4x+n) = p:q
  • Trap: Don't forget to add/subtract years from both ages in future/past scenarios
  • Check: Always verify final answer satisfies both given conditions
  • Pattern: If ages are in ratio 3:4 now and 4:5 later, set up two equations
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