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IBPS RRB PO Speed Distance Time

Study Material — 12 PYQs (2023–2023) · Concept Notes · Shortcuts

IBPS RRB PO Speed Distance Time is a frequently tested subtopic — 12 previous year questions from 2023–2023 papers are included below with concept notes, key rules and shortcut tricks.

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2023–2023
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Previous Year Questions

IBPS RRB PO Speed Distance Time — Past Exam Questions

12 questions from actual IBPS RRB PO papers · all shown free · click option to reveal solution

Exam Q 12023Previous Year Pattern

A cyclist travels at 15 km/h for 2 hours, then at 20 km/h for 3 hours. What is the average speed for the entire journey?

Exam Q 22023Previous Year Pattern

Two runners start from the same point. Runner A runs at 8 m/s and Runner B runs at 6 m/s. After how many seconds will Runner A be 100 metres ahead of Runner B?

Exam Q 32023Previous Year Pattern

A train 200 metres long crosses a platform 400 metres long in 30 seconds. What is the speed of the train in km/h?

Exam Q 42023Previous Year Pattern

A car covers 150 km at a speed of 50 km/h. How much time does it take?

Exam Q 52023Previous Year Pattern

Rajesh cycles from City A to City B at 15 km/h and returns at 10 km/h. If the total journey takes 10 hours, what is the distance between the two cities?

Exam Q 62023Previous Year Pattern

Two runners, A and B, start from the same point. A runs at 12 km/h and B runs at 8 km/h in the same direction. After how many hours will A be exactly 20 km ahead of B?

Exam Q 72023Previous Year Pattern

A car travels from P to Q at 60 km/h and from Q to P at 40 km/h. The total time for the round trip is 10 hours. What is the distance between P and Q?

Exam Q 82023Previous Year Pattern

A boat travels 48 km downstream in 3 hours and 48 km upstream in 6 hours. What is the speed of the boat in still water?

Exam Q 92023Previous Year Pattern

A train travels 240 km in 4 hours. If it increases its speed by 20%, how much distance will it cover in 5 hours at the new speed?

Exam Q 102023Previous Year Pattern

A car travels from City X to City Y at an average speed of 80 km/h. On the return journey, due to traffic, the car travels at 60 km/h. If the total time for the round trip is 14 hours, what is the distance between City X and City Y in km?

Exam Q 112023Previous Year Pattern

A train travels from Station A to Station B, a distance of 480 km. It covers the first 240 km at 60 km/h and the remaining distance at 80 km/h. A car travels the same route at a constant speed and takes the same total time as the train. What is the speed of the car in km/h?

Exam Q 122023Previous Year Pattern

A boat travels 60 km upstream and 90 km downstream in a total of 12 hours. The speed of the boat in still water is 12.5 km/h. What is the speed of the current in km/h?

Concept Notes

Speed Distance Time— Rules & Concept

1.Core Concept

Read this first — the foundation of the topic

Speed, Distance, and Time form the foundation of motion problems in SSC CGL. This topic appears in 2-3 questions per exam and requires strong formula application skills. Core Concept: Speed measures how fast an object moves. Distance is the path covered. Time is the duration taken. These three are linked by a simple relationship that forms the base of all calculations.

2.Formula Block

Memorise — at least one formula appears in every paper
• Speed = Distance/Time (S = D/T)
• Distance = Speed × Time (D = S × T)
• Time = Distance/Speed (T = D/S)
• 1 km/hr = 5/18 m/s

Unit Conversions (Critical for SSC):

• km/hr to m/s: Multiply by 5/18

• m/s to km/hr: Multiply by 18/5

3.Exam Patterns

What examiners ask — read before attempting PYQs
Shortcut 1 - Unit Conversion Trick

To convert km/hr to m/s, multiply by 5/18

Remember

36 km/hr = 10 m/s (this is a standard conversion to memorize)

Shortcut 2 - Distance Formula Rearrangement

When speed increases by x%, new time = Original time × 100/(100+x) When speed decreases by x%, new time = Original time × 100/(100-x)

4.Worked Example

Solve this step-by-step before moving on
1
Step 1

Find speed in km/hr Speed = Distance/Time = 180/3 = 60 km/hr

2
Step 2

Convert to m/s Speed in m/s = 60 × 5/18 = 300/18 = 16.67 m/s Answer: 16.67 m/s Worked Example 2: A train running at 54 km/hr takes 20 seconds to cross a platform 200m long. Find the length of the train.

1
Step 1

Convert speed to m/s 54 km/hr = 54 × 5/18 = 15 m/s

2
Step 2

Find total distance covered Distance = Speed × Time = 15 × 20 = 300m

3
Step 3

Find train length Train length = Total distance - Platform length = 300 - 200 = 100m Answer: 100 meters Shortcut 3 - Relative Speed: • Same direction: Relative speed = |S1 - S2| • Opposite direction: Relative speed = S1 + S2 Most Common Trap (#1 Mistake): Students forget unit conversions! SSC deliberately mixes km/hr and m/s in the same question. Always check units in options and convert accordingly. Questions asking for train crossing times usually need m/s, while car journey problems often use km/hr. Another frequent error is confusing relative motion directions. When two objects move toward each other, add their speeds. When moving in the same direction, subtract speeds. Time-based problems often trick students with percentage changes in speed. Remember: if speed increases by 25%, time decreases by 20% (not 25%). Use the reciprocal relationship carefully. Practice identifying whether the question asks for train length, crossing time, or platform length. Each requires different approaches but uses the same core formula.

Key Points to Remember

  • Master formula: Speed = Distance/Time and its variations D = S × T and T = D/S
  • Unit conversion: km/hr to m/s multiply by 5/18, m/s to km/hr multiply by 18/5
  • Standard conversion: 36 km/hr = 10 m/s (memorize this)
  • Relative speed: same direction subtract speeds, opposite direction add speeds
  • Train problems: Total distance = Train length + Platform/Bridge length
  • Speed increase by x%: New time = Original time × 100/(100+x)
  • Speed decrease by x%: New time = Original time × 100/(100-x)
  • Always check units in answer options before solving
  • Average speed = Total distance/Total time (not average of individual speeds)
  • Time and speed are inversely proportional when distance is constant

Exam-Specific Tips

  • 1 km/hr equals exactly 5/18 m/s
  • 36 km/hr equals exactly 10 m/s
  • 72 km/hr equals exactly 20 m/s
  • Average speed formula: Total distance divided by total time
  • Relative speed when objects move toward each other: Sum of individual speeds
  • Relative speed when objects move in same direction: Difference of individual speeds
  • When speed increases by 20%, time decreases by 16.67%
  • When speed decreases by 20%, time increases by 25%

60-Second Revision — Speed Distance Time

  • Formula: Speed = Distance/Time, Distance = Speed × Time, Time = Distance/Speed
  • Remember: 36 km/hr = 10 m/s for quick conversions
  • Unit conversion: km/hr to m/s multiply by 5/18
  • Trap: Always check if answer needs km/hr or m/s units
  • Relative speed: Add for opposite directions, subtract for same direction
  • Train crossing: Distance = Train length + Platform length
  • Speed-time relationship: Inversely proportional when distance is constant
Relative Speed→
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IBPS RRB PO Speed Distance Time — Study Material, 12 PYQs & Practice MCQs | ZestExam