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SYSTEM OF LINEAR EQUATIONS — MATRICES & DETERMINANTS ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
CORE CONCEPT ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
A system of linear equations is a group of two or more equations with the same set of unknowns (like x, y, z). We want to find values of x, y, z that satisfy ALL equations at the same time. Using matrices, we can solve these systems quickly and systematically. The standard form of 3 equations in 3 unknowns:
a1x + b1y + c1z = d1 a2x + b2y + c2z = d2
a3x + b3y + c3z = d3 This is written in matrix form as: AX = B
Where A is the coefficient matrix, X is the column matrix of unknowns, and B is the column matrix of constants. ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
KEY RULES — CONSISTENCY OF THE SYSTEM ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
The most tested concept is whether the system is CONSISTENT (has solution) or INCONSISTENT (no solution). Case 1 — det(A) ≠ 0:
The system has a UNIQUE solution. Use Cramer's Rule or inverse matrix method. Case 2 — det(A) = 0 AND the augmented matrix [A|B] has the same rank as A:
The system has INFINITELY MANY solutions (dependent equations). Case 3 — det(A) = 0 AND rank of [A|B] > rank of A:
The system has NO solution (inconsistent). ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
CRAMER'S RULE
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━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━ NDA most commonly asks: 1. Is the given system consistent or inconsistent? 2. Find the solution using Cramer's Rule. 3. For what value of k does the system have no solution or infinite solutions? 4.
Homogeneous systems — does it have only trivial solution or non-trivial? For HOMOGENEOUS system (B = 0): AX = 0 — If det(A) ≠ 0 → Only trivial solution (x=y=z=0) — If det(A) = 0 → Non-trivial (infinite) solutions exist ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━ SHORTCUT / TRICK ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━ TRICK 1 — The Determinant Shortcut: Always calculate det(A) FIRST. If det(A) ≠ 0, directly write 'unique solution exists' and use Cramer's Rule. Do not waste time checking rank. TRICK 2 — For 'value of k' type questions: Set det(A) = 0 and solve for k. This gives you the critical value.
Then check one equation from the system to decide if it's infinite solutions or no solution. ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
Write coefficient matrix A: A = |2 1| |1 3|
Find D = det(A) D = (2×3) − (1×1) = 6 − 1 = 5
Find D1 (replace column 1 with B = [5, 10]) D1 = |5 1| |10 3| D1 = (5×3) − (1×10) = 15 − 10 = 5
Find D2 (replace column 2 with B) D2 = |2 5| |1 10| D2 = (2×10) − (5×1) = 20 − 5 = 15
Apply Cramer's Rule x = D1/D = 5/5 = 1 y = D2/D = 15/5 = 3 Answer: x = 1, y = 3 Verification: 2(1) + 3 = 5 ✓ and 1 + 3(3) = 10 ✓ ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━ Students confuse det(A) = 0 with 'no solution'. Remember — det(A) = 0 means EITHER no solution OR infinite solutions. You MUST check the augmented matrix [A|B] to decide which one.
This distinction is heavily tested in NDA.
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