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NDA Dual Nature of Radiation & Matter

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This page covers NDA Dual Nature of Radiation & Matter with complete concept notes, 18 graded practice MCQs, key points and exam-specific tips. Free to study.

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Dual Nature of Radiation & Matter — Practice Questions

18graded MCQs · easy to hard · full solution & trap analysis

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Practice 1easy

A photon of frequency 6 × 10¹⁵ Hz is incident on a metal surface. If the Planck's constant h = 6.63 × 10⁻³⁴ J·s, calculate the energy of the photon.

Practice 2easy

An electron accelerated through a potential difference of 50 V has a de Broglie wavelength of 1.73 × 10⁻¹⁰ m. Which statement correctly describes the dual nature illustrated here?

Practice 3easy

The de Broglie wavelength of a moving particle is given by λ = h/p. If an electron (mass = 9.1 × 10⁻³¹ kg) moves with velocity 2 × 10⁶ m/s, calculate its de Broglie wavelength. (h = 6.63 × 10⁻³⁴ J·s)

Practice 4easy

In the photoelectric effect, Einstein's photon theory explains that light consists of discrete energy packets. Which phenomenon directly proves the particle nature of radiation?

Practice 5easy

A light wave of wavelength 500 nm is diffracted through a slit, and simultaneously, individual photons from this light eject electrons from a photoelectric surface. Which aspect of dual nature is demonstrated respectively?

Practice 6medium

A photon of frequency 6 × 10¹⁵ Hz is incident on a metal surface. Calculate the energy of this photon. (Given: h = 6.63 × 10⁻³⁴ J·s)

Practice 7medium

According to de Broglie's hypothesis, the wavelength of a matter wave is inversely proportional to which quantity?

Practice 8medium

An electron moves with a velocity of 2 × 10⁶ m/s. Calculate its de Broglie wavelength. (Given: h = 6.63 × 10⁻³⁴ J·s, mₑ = 9.11 × 10⁻³¹ kg)

Practice 9medium

Which phenomenon directly proves the particle nature of light?

Practice 10medium

Light of wavelength 500 nm is incident on a metal surface with work function 2.0 eV. Calculate the maximum kinetic energy of ejected electrons. (Given: h = 6.63 × 10⁻³⁴ J·s, c = 3 × 10⁸ m/s, 1 eV = 1.6 × 10⁻¹⁹ J)

Practice 11medium

The stopping potential for photoelectrons ejected from a metal is 2.5 V when light of frequency 8 × 10¹⁴ Hz is used. Calculate the work function of the metal. (Given: h = 6.63 × 10⁻³⁴ J·s, e = 1.6 × 10⁻¹⁹ C)

Practice 12medium

Which of the following correctly represents Einstein's photoelectric equation?

Practice 13medium

A proton and an electron both have the same momentum. Which particle has a larger de Broglie wavelength?

Practice 14medium

The threshold frequency for a metal is 5 × 10¹⁴ Hz. What is the work function of the metal? (Given: h = 6.63 × 10⁻³⁴ J·s)

Practice 15hard

An electron with de Broglie wavelength λ₁ is accelerated through a potential difference of 100 V. If it is then accelerated through an additional 300 V (total 400 V), its new de Broglie wavelength λ₂ becomes:

Practice 16hard

A photon and an electron both have the same de Broglie wavelength of 1.2 × 10⁻¹⁰ m. If the photon energy is 10.4 keV, what is the kinetic energy of the electron (in eV)? [Use: h = 6.63 × 10⁻³⁴ J·s, c = 3 × 10⁸ m/s, mₑ = 9.1 × 10⁻³¹ kg]

Practice 17hard

The stopping potential for photoelectric effect is 3.0 V when light of wavelength 300 nm is incident on a metal surface. What is the work function of the metal?

Practice 18hard

An alpha particle (mass 4 u, charge +2e) and a proton (mass 1 u, charge +e) are both accelerated from rest through the same potential difference. The ratio of their de Broglie wavelengths (λₐ/λₚ) is:

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