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RRB Group D Successive Profit & Loss

Study Material — 1 PYQs (2019–2019) · Concept Notes · Shortcuts

RRB Group D Successive Profit & Loss is a frequently tested subtopic — 1 previous year questions from 2019–2019 papers are included below with concept notes, key rules and shortcut tricks.

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2019–2019
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8 Key Points
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Previous Year Questions

RRB Group D Successive Profit & Loss — Past Exam Questions

1 questions from actual RRB Group D papers · all shown free · click option to reveal solution

Exam Q 12019Previous Year Pattern

A shopkeeper buys an article and sells it at a profit of 20%. If he had bought it at 10% less and sold it for ₹6 more, he would have gained 40%. What is the original cost price of the article?

Concept Notes

Successive Profit & Loss— Rules & Concept

Core ConceptRead this first — the foundation of the topic
Core Concept

When profits and losses are applied one after another, we cannot simply add or subtract the percentages. Each percentage change acts on the new value, not the original price

Key Rules

If successive changes of a% and b% occur, the net effect formula is: Net% = a + b + (ab)/100. Use positive values for profit and negative values for loss. For three successive changes a%, b%, c%, first find net effect of any two, then apply the third change.

Formula BlockMemorise — at least one formula appears in every paper
• Two successive changes: Net% = a + b + (ab)/100
• Selling price after successive changes: SP = CP × (100+a)/100 × (100+b)/100
• Overall profit/loss = Net% of original cost price
Exam PatternsWhat examiners ask — read before attempting PYQs

Questions typically involve 2-3 successive transactions. Common scenarios include buying-selling chains, discount followed by profit, or multiple markups. SSC often asks for overall profit/loss percentage or final selling price.

ShortcutsUse these to save 30–60 seconds per question

For quick calculation, convert percentages to multipliers. 20% profit = 1.2, 10% loss = 0.9. Multiply all factors: 1.2 × 0.9 = 1.08 = 8% overall profit.

Worked ExampleSolve this step-by-step before moving on
1
Step 1

Identify the changes First transaction: +20% (profit) Second transaction: -10% (loss)

2
Step 2

Apply the formula Net% = a + b + (ab)/100 Net% = 20 + (-10) + (20 × (-10))/100 Net% = 20 - 10 - 200/100 Net% = 10 - 2 = 8%

3
Step 3

Verify using multiplier method Final value = 1000 × 1.20 × 0.90 = 1000 × 1.08 = 1080 Profit = 1080 - 1000 = 80 Profit% = 80/1000 × 100 = 8% Answer: 8% overall profit Alternate Method using SP calculation: After first sale: 1000 × 120/100 = 1200 After second sale: 1200 × 90/100 = 1080 Net profit = 1080 - 1000 = 80 Profit% = 8%

Exam TrapsCommon mistakes students make — avoid these

Students often add percentages directly (20% - 10% = 10%) ignoring the compounding effect. Always remember that each subsequent percentage works on the changed value, not the original price. The interaction term (ab)/100 is crucial and frequently overlooked.

Key Points to Remember

  • Successive changes cannot be added directly due to compounding effect
  • Formula for two changes: Net% = a + b + (ab)/100
  • Use positive values for profit, negative for loss in the formula
  • Multiplier method: Convert percentages to decimals and multiply
  • Each subsequent change acts on the new value, not original price
  • Interaction term (ab)/100 is often the key to correct answers
  • Three changes: Find net of first two, then apply third change
  • Final amount = Original × (100+a)/100 × (100+b)/100

Exam-Specific Tips

  • Net percentage formula for successive changes: a + b + (ab)/100
  • 20% profit converts to multiplier 1.2, 25% loss converts to 0.75
  • For equal successive profits of x%, net effect is x + x + x²/100
  • Two successive discounts of 10% each give net discount of 19%
  • Successive changes of +50% and -20% result in +20% net change
  • Three successive profits of 10% each give net profit of 33.1%
  • Formula remains same whether dealing with CP, SP, or marked price
Practice MCQs

Successive Profit & Loss — Practice Questions

3graded MCQs · easy to hard · full solution & trap analysis

All MCQs →
Practice 1easy

A shopkeeper buys an item at ₹500. He marks it up by 20% and then offers a discount of 10% on the marked price. Later, he sells the remaining stock at a further discount of 5% on the already discounted price. What is his overall profit percentage on the item?

Practice 2medium

A shopkeeper buys an item at ₹500. He marks it up by 40% and then offers a discount of 10% on the marked price. Later, he sells the remaining stock at a further discount of 20% on the already discounted price. What is his overall profit percentage on the items sold in the second batch?

Practice 3hard

A shopkeeper buys goods at a certain price. He marks up the price by 40% and then offers two successive discounts of 10% and 15% on the marked price. Later, he realizes he made an error in his cost calculation and actually paid 20% less than he initially thought. If his final profit percentage (based on the actual cost) is 1.92%, find the marked price as a percentage of the actual cost price.

60-Second Revision — Successive Profit & Loss

  • Remember: Net% = a + b + (ab)/100 for two successive changes
  • Trick: Use multipliers for faster calculation - multiply all factors
  • Formula: SP = CP × (100+a)/100 × (100+b)/100
  • Trap: Never add successive percentages directly
  • Method: For three changes, find net of any two first, then apply third
  • Quick check: Positive result means profit, negative means loss
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