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RRB NTPC Cylinder, Cone, Sphere

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This page covers RRB NTPC Cylinder, Cone, Sphere with complete concept notes, 25 graded practice MCQs, key points and exam-specific tips. Free to study.

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Concept Notes

Cylinder, Cone, Sphere— Rules & Concept

Core ConceptRead this first — the foundation of the topic

Cylinder, Cone, and Sphere are the three most important 3D shapes in SSC CGL. These appear in 2-3 questions every year, making them high-scoring topics. Understanding their formulas and relationships is crucial for exam success. Core Concepts:

A Cylinder is like a circular tube - think of a water pipe or tin can. It has two circular ends and a curved surface. A Cone is like an ice cream cone - one circular base and comes to a point at the top.

A Sphere is a perfect ball - like a football or marble.

Formula BlockMemorise — at least one formula appears in every paper

Block:

Cylinder: Volume = πr²h, Curved Surface Area = 2πrh, Total Surface Area = 2πr(r+h)
Cone: Volume = (1/3)πr²h, Curved Surface Area = πrl, Total Surface Area = πr(r+l), where l = √(r²+h²)
Sphere: Volume = (4/3)πr³, Surface Area = 4πr²
Exam PatternsWhat examiners ask — read before attempting PYQs

SSC CGL typically asks: volume calculations (40%), surface area problems (35%), and mixed problems involving two shapes (25%). Questions often involve finding radius, height, or comparing volumes.

ShortcutsUse these to save 30–60 seconds per question
Volume Ratio Trick

Cylinder:Cone:Sphere with same radius and height = 3:1:4 (when sphere diameter = cylinder height) 2

Quick Surface Area

For cylinder, if radius = height, then Total SA = 6πr² 3

Cone Slant Height

Use 3-4-5 triangle ratios when possible

Worked ExampleSolve this step-by-step before moving on
1
Step 1

Volume = πr²h = (22/7) × 7² × 10 = (22/7) × 49 × 10 = 22 × 7 × 10 = 1540 m³

2
Step 2

Total SA = 2πr(r+h) = 2 × (22/7) × 7 × (7+10) = 44 × 17 = 748 m² Worked Example 2: A cone and sphere have the same radius 6cm. If cone's height is 8cm, find the ratio of their volumes.

1
Step 1

Cone volume = (1/3)πr²h = (1/3) × π × 6² × 8 = 96π cm³

2
Step 2

Sphere volume = (4/3)πr³ = (4/3) × π × 6³ = (4/3) × π × 216 = 288π cm³

3
Step 3

Ratio = 96π : 288π = 1:3 Most Common Trap: Students confuse slant height (l) with actual height (h) in cone problems. Remember: slant height is the distance from base edge to apex, while height is perpendicular distance from base to apex. Always check if the given measurement is l or h before applying formulas. Another frequent mistake is forgetting to use 'curved surface area' vs 'total surface area'. Read questions carefully - if a cylinder has open ends, use curved surface area only.

Key Points to Remember

  • Cylinder volume = πr²h, remember to multiply base area by height
  • Cone volume is exactly 1/3 of cylinder volume with same base and height
  • Sphere volume formula: (4/3)πr³ - memorize this fraction carefully
  • Cylinder total surface area = 2πr(r+h) - factor out 2πr for speed
  • Cone slant height l = √(r²+h²) using Pythagoras theorem
  • Sphere surface area = 4πr² - exactly 4 times the great circle area
  • Volume ratio shortcut: Cylinder:Cone:Sphere = 3:1:4 (same r and h)
  • For cylinder CSA problems, use 2πrh (curved surface only)
  • Cone total SA = πr(r+l) where l is slant height, not vertical height
  • Common trap: always distinguish between slant height and vertical height in cones

Exam-Specific Tips

  • Value of π in SSC calculations is typically 22/7 or 3.14
  • Volume of cone is always 1/3 times volume of cylinder with same base and height
  • Sphere has minimum surface area for given volume among all 3D shapes
  • Hemisphere volume = (2/3)πr³ and surface area = 3πr²
  • Cylinder with radius = height has total surface area = 6πr²
  • Cone with base radius = height has slant height = r√2
  • Volume of sphere inscribed in cube of side 'a' = (π/6)a³
  • Ratio of volumes of cube to inscribed sphere = 6:π
Practice MCQs

Cylinder, Cone, Sphere — Practice Questions

25graded MCQs · easy to hard · full solution & trap analysis · showing 20 of 25

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Practice 1easy

A cylinder has a volume of 1540 cm³ and a height of 10 cm. What is its radius? (Use π = 22/7)

Practice 2easy

A cone has a base radius of 8 cm and height of 15 cm. What is its slant height?

Practice 3easy

The volume of a sphere is 288π cm³. What is its radius? (Use π = 22/7)

Practice 4easy

A sphere has a surface area of 616 cm². What is its radius? (Use π = 22/7)

Practice 5easy

A cylinder and a cone have the same radius of 5 cm and the same height of 12 cm. What is the ratio of their volumes?

Practice 6easy

A sphere has a radius of 7 cm. What is its surface area? (Use π = 22/7)

Practice 7medium

A sphere has a surface area of 616 cm². What is its volume? [Use π = 22/7]

Practice 8medium

The curved surface area of a cone is 550 cm² and its slant height is 25 cm. What is the radius of the base? [Use π = 22/7]

Practice 9medium

The curved surface area of a cone is 550 cm² and its slant height is 25 cm. Find the radius of the base of the cone.

Practice 10medium

A cylindrical tank has radius 5 m and height 12 m. It is filled with water up to a height of 9 m. A solid cone with radius 5 m and height 6 m is completely submerged in the tank. By how much does the water level rise (in metres)?

Practice 11medium

Two spheres have radii in the ratio 2:3. What is the ratio of their volumes?

Practice 12medium

A solid sphere of radius 6 cm is melted and recast into a cone with base radius 6 cm. What is the height of the cone?

Practice 13medium

A cylinder and a cone have the same base radius of 5 cm and the same height of 12 cm. What is the ratio of their volumes?

Practice 14medium

A cone has a base radius of 6 cm and slant height of 10 cm. What is the curved surface area of the cone?

Practice 15medium

A cylinder has a radius of 7 cm and height of 10 cm. If the radius is increased by 50% and height remains the same, by what percentage does the volume increase?

Practice 16medium

A sphere has a radius of 6 cm. If the radius is increased by 50%, what is the percentage increase in the volume of the sphere?

Practice 17medium

A solid cylinder has radius 7 cm and height 10 cm. A cone with the same base radius and height is carved out from it. What is the volume of the remaining solid (in cm³)?

Practice 18hard

A solid metallic sphere of radius 6 cm is melted and recast into a solid cone with base radius 4 cm. Find the height of the cone (in cm).

Practice 19hard

A cylinder has radius 5 cm and height 12 cm. A cone with the same base radius and height is removed from the top. What is the remaining volume (in cm³)?

Practice 20hard

Two spheres have radii in the ratio 2:3. If the surface area of the smaller sphere is 144π cm², find the surface area of the larger sphere (in cm²).

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60-Second Revision — Cylinder, Cone, Sphere

  • Remember: Cone volume = (1/3) × Cylinder volume for same base and height
  • Formula check: Sphere SA = 4πr², Volume = (4/3)πr³
  • Trap: Distinguish cone's slant height (l) from vertical height (h)
  • Quick ratio: Cylinder:Cone:Sphere volumes = 3:1:4 (same dimensions)
  • Surface area: Cylinder = 2πr(r+h), Cone = πr(r+l), Sphere = 4πr²
  • Shortcut: Use π = 22/7 for calculations involving multiples of 7
  • Check question: Curved SA vs Total SA - open vs closed surfaces
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