Question 1

Four people—Vikram, Wina, Xander, Yuki—have different ages. Vikram is older than Wina. Xander is younger than Yuki. Wina is older than Xander. Who is the youngest?

Accepted Answer

Age comparison puzzle requiring transitive ordering. Constraints: Vikram > Wina, Yuki > Xander, Wina > Xander. Chain: Vikram > Wina > Xander and Yuki > Xander. Combining: Vikram > Wina > Xander and Yuki > Xander. To find youngest, identify who is smaller than all others. Xander < Wina and Xander < Yuki. Is Xander < Vikram? Yes, because Vikram > Wina > Xander. Therefore Xander is smallest. Xander is the youngest.

Question 2

Five items—Apple, Banana, Cherry, Date, Elderberry—are arranged by price (lowest to highest). Apple costs less than Cherry. Banana costs less than Date. Cherry costs less than Elderberry. Date costs less than Elderberry. Which item is definitely more expensive than at least three other items?

Accepted Answer

Comparison puzzle requiring identification of an item's minimum rank in the ordering. Constraints: Apple < Cherry < Elderberry, Banana < Date < Elderberry. Build chains: Chain 1: Apple < Cherry < Elderberry. Chain 2: Banana < Date < Elderberry. Merge: Elderberry is at the top (most expensive). Both chains lead to Elderberry. Now, where do the chains intersect? We know: Apple < Cherry < Elderberry and Banana < Date < Elderberry. We don't know the relative order of {Apple, Banana} or {Cherry, Date}. Possible orderings: (1) Apple, Banana, Cherry, Date, Elderberry. (2) Apple, Cherry, Banana, Date, Elderberry. (3) Banana, Apple, Cherry, Date, Elderberry. (4) Banana, Apple, Date, Cherry, Elderberry. (5) Apple, Banana, Date, Cherry, Elderberry. And others. In all valid orderings, Elderberry is 5th (most expensive), so Elderberry is more expensive than 4 items. Cherry appears in positions 2, 3, or 4 depending on arrangement. Date appears in positions 3 or 4. The item that is definitely more expensive than at least 3 others must appear in position 3 or higher in all valid orderings. Elderberry is always position 5 (more expensive than 4 items). Cherry is always above Elderberry but below or above Banana and Date. Testing: In ordering (1), Cherry is 3rd (more expensive than 2). In ordering (2), Cherry is 3rd (more expensive than 2). In ordering (5), Cherry is 4th (more expensive than 3). So Cherry is not always more expensive than 3. Date: In ordering (1), Date is 4th (more expensive than 3). In ordering (2), Date is 4th (more expensive than 3). In ordering (5), Date is 3rd (more expensive than 2). So Date is not always more expensive than 3. Elderberry: Always 5th (more expensive than 4). Answer: Elderberry.

Question 3

Five friends—Arun, Bhavna, Chetan, Deepa, and Esha—are sitting in a row facing North. Based on the following clues, who sits third from the left?

1. Arun sits immediately to the left of Bhavna.
2. Deepa sits immediately to the right of Chetan.
3. Esha sits at one of the ends.
4. Chetan does not sit at either end.

Who sits third from the left?

Accepted Answer

This is a linear arrangement puzzle requiring systematic constraint satisfaction. From clue 3, Esha is at position 1 or 5. From clue 4, Chetan is at position 2, 3, or 4. From clues 1 and 2, Arun-Bhavna and Chetan-Deepa form consecutive pairs. Testing Esha at position 1: Remaining positions are 2-5 for Arun, Bhavna, Chetan, Deepa. If Chetan is at position 2, Deepa is at position 3 (clue 2). Then Arun-Bhavna occupy positions 4-5 (clue 1). This gives: Esha(1), Chetan(2), Deepa(3), Arun(4), Bhavna(5). All constraints satisfied. Position 3 = Deepa.

Question 4

In a row of four people sitting in a line, Priya sits third from the left. Qasim sits to the immediate right of Priya. Which position does Qasim occupy?

Accepted Answer

Priya sits third from the left means she is in position 3. Qasim sits immediately to the right of Priya, so Qasim is in position 4 (the rightmost position in a 4-person line).

Question 5

Five friends—Arun, Bhavna, Chitra, Deepak, and Esha—sit in two parallel rows of 5 seats each. Row 1 faces Row 2. Arun sits in Row 1, Position 3. Bhavna sits directly opposite Arun in Row 2. Chitra sits to the immediate left of Arun. Deepak sits to the immediate right of Bhavna. Esha sits in Row 1, Position 1. Who sits in Row 2, Position 2?

Accepted Answer

This is a parallel row puzzle requiring careful tracking of positions and opposite relationships. Students must identify the person in a specific cell by using direct clues and elimination.

Question 6

Six people—P, Q, R, S, T, U—sit in two parallel rows facing each other. Row A has 3 people, Row B has 3 people. P sits in Row A, Position 2. Q sits directly opposite P. R sits to the left of P in Row A. S sits to the right of Q in Row B. T sits in Row A, Position 3. U sits in Row B, Position 1. Who sits in Row B, Position 2?

Accepted Answer

A parallel row puzzle with 3-seat rows, testing position mapping and opposite relationships in a compact setup.

Question 7

Seven people sit in two parallel rows. Row 1 has 4 people, Row 2 has 3 people. Vikram sits in Row 1, Position 2. Priya sits directly opposite Vikram. Anuj sits to the immediate left of Vikram. Neha sits to the immediate right of Priya. Ravi sits in Row 1, Position 4. Sanjay sits in Row 2, Position 1. Who sits in Row 2, Position 3?

Accepted Answer

A parallel row puzzle with unequal row sizes, testing whether students can correctly apply opposite relationships when rows have different lengths.

Question 8

Four people—Mohan, Geeta, Arjun, and Divya—sit in two parallel rows of 2 seats each. Row X faces Row Y. Mohan sits in Row X, Position 1. Geeta sits directly opposite Mohan. Arjun sits to the right of Mohan in Row X. Divya sits in Row Y, Position 2. Who sits in Row Y, Position 1?

Accepted Answer

A minimal parallel row puzzle (2×2 grid) testing basic opposite relationships and adjacency in the simplest configuration.

Question 9

Eight people sit in two parallel rows of 4 seats each. Row North faces Row South. Kavya sits in Row North, Position 3. Ishaan sits directly opposite Kavya. Jaya sits to the left of Kavya. Laxman sits to the right of Ishaan. Mira sits in Row North, Position 1. Neeraj sits in Row South, Position 1. Who sits in Row South, Position 4?

Accepted Answer

A standard 4×4 parallel row puzzle testing position mapping with multiple adjacency and opposite constraints.

Question 10

Five people—Aman, Bhavna, Chitra, Deepak, and Esha—live in a 5-storey building, one person per floor (floors numbered 1 to 5 from bottom to top). The following conditions apply:
1. Aman lives on an odd-numbered floor.
2. Bhavna lives directly above Chitra.
3. Deepak lives on floor 3.
4. Esha lives on a floor higher than Deepak's.
5. Chitra does not live on floor 1.

Who lives on floor 2?

Accepted Answer

Using the constraints: Deepak is on floor 3 (given). Esha must be on floor 4 or 5 (higher than floor 3). Bhavna is directly above Chitra, and Chitra is not on floor 1, so Chitra-Bhavna pairs can be: (2,3), (3,4), or (4,5). Since Deepak occupies floor 3, the pair cannot be (2,3) or (3,4). Thus Chitra is on floor 4 and Bhavna on floor 5. This leaves floors 1 and 2 for Aman and Esha. Aman must be on an odd floor (1, 3, or 5), but 3 and 5 are taken, so Aman is on floor 1. Therefore, Esha is on floor 2.

Question 11

Five people — Aman, Bhavna, Chetan, Deepa, and Esha — live on five different floors of a building (floors 1 to 5, where floor 1 is the ground floor). Based on the following clues, determine who lives on floor 3.

Clue 1: Aman lives on an odd-numbered floor.
Clue 2: Bhavna lives immediately above Chetan.
Clue 3: Deepa lives on floor 2.
Clue 4: Esha lives on a floor higher than Deepa but lower than floor 5.
Clue 5: Chetan does not live on floor 1.

Accepted Answer

From Clue 3, Deepa is on floor 2. From Clue 4, Esha is on floor 3 or 4 (higher than 2, lower than 5). From Clue 2, Bhavna is immediately above Chetan, so they occupy consecutive floors. From Clue 5, Chetan is not on floor 1. From Clue 1, Aman is on floor 1, 3, or 5. Since Deepa occupies floor 2, the remaining people (Aman, Bhavna, Chetan, Esha) occupy floors 1, 3, 4, 5. If Chetan is on floor 3, Bhavna is on floor 4. Then Esha must be on floor 3 or 4 (Clue 4), but both are taken by Chetan and Bhavna — contradiction. If Chetan is on floor 4, Bhavna is on floor 5. Then Esha must be on floor 3 or 4. Since floor 4 is Chetan's, Esha is on floor 3. This leaves Aman on floor 1. Check: Aman on floor 1 (odd ✓), Bhavna on floor 5 immediately above Chetan on floor 4 ✓, Deepa on floor 2 ✓, Esha on floor 3 (higher than 2, lower than 5 ✓), Chetan on floor 4 (not floor 1 ✓). Therefore, Esha lives on floor 3.

Question 12

Six friends—Aman, Bhavna, Chirag, Diya, Eshan, and Fiona—sit in two parallel rows of 3 seats each. Row 1 faces Row 2. The following conditions apply:

1. Aman sits in Row 1, middle position.
2. Bhavna sits directly opposite to Aman in Row 2.
3. Chirag sits to the left of Aman in Row 1.
4. Diya sits to the right of Bhavna in Row 2.
5. Eshan sits in Row 1, right position.
6. Fiona sits in the remaining seat.

Who sits directly opposite to Chirag?

Accepted Answer

This is a parallel row seating puzzle requiring students to map positions in two facing rows using direct and relative position clues. The solution involves placing each person systematically and identifying the person opposite to a specific individual.

Question 13

Four students—Vikram, Wanda, Xavier, and Yuki—sit in a line facing East. Xavier sits second from the left. Vikram sits to the immediate left of Xavier. What is Vikram's position from the left?

Accepted Answer

Xavier sits second from the left, meaning Xavier is in position 2. Vikram sits immediately to the left of Xavier, meaning Vikram is in position 1 (the leftmost position).

Question 14

Five employees—Arun, Bhavna, Chitra, Deepak, and Esha—are scheduled to work on five consecutive days: Monday through Friday. Each works exactly one day. Based on the following clues, who works on Wednesday?

1. Arun works two days after Bhavna.
2. Chitra works on Friday.
3. Deepak works on Monday.
4. Esha works one day before Arun.

Accepted Answer

From clue 3: Deepak = Monday. From clue 2: Chitra = Friday. From clue 1: Arun = Bhavna + 2 days. From clue 4: Esha = Arun − 1 day. Combining clues 1 and 4: Esha = (Bhavna + 2) − 1 = Bhavna + 1. So Bhavna, Esha, Arun are on consecutive days with Esha between them. Remaining days are Tuesday, Wednesday, Thursday. If Bhavna = Tuesday, then Esha = Wednesday, Arun = Thursday. This satisfies all clues. Answer: Esha works on Wednesday.

Question 15

Six tasks—P, Q, R, S, T, U—must be completed on six consecutive days starting Monday. Each task takes exactly one day. Using the clues below, on which day is task R scheduled?

1. Task P is scheduled 3 days before task T.
2. Task Q is scheduled on Wednesday.
3. Task R is scheduled 1 day after task Q.
4. Task S is scheduled on Monday.

Accepted Answer

From clue 4: S = Monday. From clue 2: Q = Wednesday. From clue 3: R = Q + 1 = Thursday. From clue 1: P = T − 3. Remaining days are Tuesday, Friday, Saturday. Remaining tasks are P, T, U. If P = Tuesday, then T = Friday. U = Saturday. All clues satisfied. Answer: R is on Thursday.

Question 16

Three events—A, B, and C—are scheduled on three different days of the week: Monday, Wednesday, and Friday. Using the clues below, on which day is event B scheduled?

1. Event A is not on Monday.
2. Event B is scheduled 2 days after event C.
3. Event C is not on Friday.

Accepted Answer

From clue 2: B = C + 2 days. Possible pairs from {Mon, Wed, Fri}: (C=Mon, B=Wed), (C=Wed, B=Fri). From clue 3: C ≠ Fri. Both pairs satisfy clue 3. From clue 1: A ≠ Mon. If (C=Mon, B=Wed), then A=Fri. Clue 1 is satisfied (A=Fri ≠ Mon). If (C=Wed, B=Fri), then A=Mon. Clue 1 is violated (A=Mon). So the first case holds: C=Mon, B=Wed, A=Fri. Answer: Event B is on Wednesday.

Question 17

Six employees—M, N, O, P, Q, R—work on 6 different floors of an office building (floors 1 to 6). Each employee is on exactly one floor. Based on the clues below, who works on floor 4?

Clue 1: M works on an even-numbered floor.
Clue 2: N works exactly 2 floors above O.
Clue 3: P works on floor 1.
Clue 4: Q works on floor 6.
Clue 5: R works on floor 2.
Clue 6: O works on floor 3.

Accepted Answer

From the clues: P=1 (Clue 3), R=2 (Clue 5), O=3 (Clue 6), Q=6 (Clue 4). From Clue 2: N is 2 floors above O. Since O=3, N=5. Remaining: M for floor 4. From Clue 1: M works on an even-numbered floor. Floor 4 is even. Therefore, M=4.

Question 18

A company schedules meetings for six months: January to June. Each month has exactly one meeting. The following constraints apply:
1. The February meeting is 2 weeks before the March meeting.
2. The April meeting is 3 weeks after the March meeting.
3. The January meeting is on the 15th.
4. The May meeting is on the 10th.
5. The June meeting is 1 week after the May meeting.

On which date does the April meeting occur?

Accepted Answer

This is a day-month scheduling puzzle requiring date arithmetic and constraint chaining across multiple months.

Question 19

Seven tasks—P, Q, R, S, T, U, V—are scheduled across a week (Monday to Sunday). Each task is assigned exactly one day. The constraints are:
1. P is scheduled on Monday.
2. Q is scheduled 2 days after R.
3. S is scheduled on Friday.
4. T is scheduled on the day immediately before U.
5. V is scheduled on Sunday.
6. R is not scheduled on Wednesday.

On which day is R scheduled?

Accepted Answer

This is a weekly scheduling puzzle requiring constraint satisfaction and elimination of impossible placements based on derived constraints.

Question 20

A library schedules book releases for eight consecutive weeks (Week 1 to Week 8). Eight authors—A, B, C, D, E, F, G, H—each have their book released in exactly one week. The constraints are:
1. A's book is released in Week 1.
2. B's book is released 3 weeks after C's book.
3. D's book is released in Week 5.
4. E's book is released on the week immediately before F's book.
5. G's book is released in Week 8.
6. H's book is released in an even-numbered week.
7. C's book is not released in Week 2.

In which week is C's book released?

Accepted Answer

This is an 8-week scheduling puzzle requiring multi-constraint satisfaction, interval arithmetic, and elimination of forbidden placements.

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