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SBI Clerk Population Problems

Study Material — 14 PYQs (2020–2020) · Concept Notes · Shortcuts

SBI Clerk Population Problems is a frequently tested subtopic — 14 previous year questions from 2020–2020 papers are included below with concept notes, key rules and shortcut tricks.

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2020–2020
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Previous Year Questions

SBI Clerk Population Problems — Past Exam Questions

14 questions from actual SBI Clerk papers · all shown free · click option to reveal solution

Exam Q 12020Previous Year Pattern

A town's population decreased by 10% from 2019 to 2020. If the population in 2020 was 360,000, what was the population in 2019?

Exam Q 22020Previous Year Pattern

The population of a village increased from 80,000 to 96,000 over two years. What is the percentage increase?

Exam Q 32020Previous Year Pattern

If a district's population is 600,000 and 35% are children, how many children are there in the district?

Exam Q 42020Previous Year Pattern

A state's population was 2,000,000 in 2015. By 2025, it became 2,640,000. What is the percentage increase over this 10-year period?

Exam Q 52020Previous Year Pattern

The population of a city was 500,000 in 2020. If it increases by 20% in 2021, what will be the population in 2021?

Exam Q 62020Previous Year Pattern

The population of Town A is 2,40,000. The population of Town B is 20% more than Town A. What is the difference between the populations of Town B and Town A?

Exam Q 72020Previous Year Pattern

The population of a city was 5,00,000 in 2020. It increased by 20% in 2021 and then decreased by 10% in 2022. What is the population at the end of 2022?

Exam Q 82020Previous Year Pattern

A city's population decreased from 6,00,000 to 5,40,000 over one year. What is the percentage decrease in population?

Exam Q 92020Previous Year Pattern

The male population of a district is 3,60,000, which is 60% of the total population. What is the female population of the district?

Exam Q 102020Previous Year Pattern

A region's population was 10,00,000 in 2015. It grew by 25% from 2015 to 2018, and then declined by 20% from 2018 to 2021. What is the population in 2021?

Exam Q 112020Previous Year Pattern

The ratio of males to females in a city is 7:5. If the male population increases by 25% and the female population increases by 20%, what will be the new ratio of males to females?

Exam Q 122020Previous Year Pattern

A city's population in 2015 was P. In 2020, the population became 1.5P. If the population continues to grow at the same rate (as a percentage per year), what will be the population in 2025?

Exam Q 132020Previous Year Pattern

The population of a city increases by 20% in the first year and then decreases by 10% in the second year. If the population after two years is 216,000, what was the original population?

Exam Q 142020Previous Year Pattern

A town's population was 500,000 in 2015. It grew by 15% in 2016, then by 12% in 2017, and then declined by 8% in 2018. What is the population in 2018?

Concept Notes

Population Problems— Rules & Concept

Core ConceptRead this first — the foundation of the topic
CORE CONCEPT

Population problems follow the compound growth formula. If a population increases or decreases by a certain percentage each year, you apply that percentage repeatedly, not just once. This is different from simple interest — it's like compound interest

KEY RULES

Population grows or shrinks by a fixed percentage each year 2. The percentage applies to the NEW population each year, not the original 3. Use the compound formula, not simple addition/subtraction 4. Decrease and increase work the same way mathematically

Formula BlockMemorise — at least one formula appears in every paper
Final Population = Initial Population × (1 + r/100)^n

Where:

- r = rate of increase (use negative r for decrease)
- n = number of years
- If r = 5% increase, use (1 + 5/100) = 1.05
- If r = 10% decrease, use (1 - 10/100) = 0.90
Exam PatternsWhat examiners ask — read before attempting PYQs
1

Find final population after n years

2

Find initial population (work backwards)

3

Find rate of growth

4

Find time period

5

Mixed increase and decrease over different years

Worked ExampleSolve this step-by-step before moving on
1
Step 1

Population after Year 1 = 50,000 × (1 + 10/100) = 50,000 × 1.10 = 55,000

2
Step 2

Population after Year 2 = 55,000 × (1 + 20/100) = 55,000 × 1.20 = 66,000 Alternative Direct Method: = 50,000 × 1.10 × 1.20 = 50,000 × 1.32 = 66,000

Exam TrapsCommon mistakes students make — avoid these

Students add percentages directly: 10% + 20% = 30%, then calculate 50,000 × 1.30 = 65,000. This is WRONG because the 20% applies to the increased population, not the original. Always multiply the factors for each year.

Key Points to Remember

  • Population problems use compound growth formula: Final = Initial × (1 + r/100)^n
  • Percentage always applies to the CURRENT population, not the original amount
  • For decrease, use (1 - r/100) in the formula instead of (1 + r/100)
  • Multiple years with different rates: multiply all factors together for direct calculation
  • Never add percentages directly; always use multiplication of decimal factors
  • If asked for initial population, rearrange formula: Initial = Final ÷ (1 + r/100)^n

Exam-Specific Tips

  • Population formula: Final = Initial × (1 + r/100)^n where r is annual rate and n is years
  • For 10% increase, multiply by 1.10; for 10% decrease, multiply by 0.90
  • If population increases by p% one year and q% next year, combined factor = (1 + p/100) × (1 + q/100)
  • Compound population growth applies the percentage to the NEW amount each year, not original
  • For population decrease problems, the formula remains the same but r is treated as negative
  • Quick check: 50,000 population growing at 10% annually for 2 years = 50,000 × 1.21 = 60,500

60-Second Revision — Population Problems

  • Formula: Final Population = Initial × (1 + r/100)^n — this is compound, not simple
  • Trap: Never add percentages from different years. Multiply the growth factors instead
  • Decrease: Use negative r or write (1 - r/100) — both methods give same answer
  • Multi-year: For different rates each year, write as Initial × (1.10) × (1.20) × (0.95) etc.
  • Reverse: If given final population, divide backwards: Initial = Final ÷ [(1 + r/100)^n]
  • Quick mental check: 10% increase twice ≈ 21% total (not 20%), because second 10% acts on larger base
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