Question 1

A person spends 35% of his income on rent, 25% on food, and 20% on utilities. If he saves ₹8000, what is his total monthly income?

Accepted Answer

Step 1: Total spending percentage = 35% + 25% + 20% = 80%. Step 2: Savings percentage = 100% - 80% = 20%. Step 3: If 20% of income = 8000, then income = 8000 ÷ 0.20 = 40,000.

Question 2

A student scored 72% in an exam and obtained 360 marks. What was the maximum marks for the exam?

Accepted Answer

Step 1: Let maximum marks = x. Step 2: 72% of x = 360. Step 3: 0.72 × x = 360. Step 4: x = 360 ÷ 0.72 = 500.

Question 3

A shopkeeper marks his goods 40% above the cost price. If he gives a discount of 10% on the marked price, what is his profit percentage?

Accepted Answer

Step 1: Let cost price = 100. Marked price = 100 + 40% of 100 = 140. Step 2: Discount = 10% of 140 = 14. Selling price = 140 - 14 = 126. Step 3: Profit = 126 - 100 = 26. Profit percentage = (26/100) × 100 = 26%.

Question 4

The price of a commodity increased by 20% and then decreased by 20%. What is the net change in price?

Accepted Answer

Step 1: Let original price = 100. Step 2: After 20% increase: 100 + 20 = 120. Step 3: After 20% decrease on 120: 120 - (20% of 120) = 120 - 24 = 96. Step 4: Net change = 96 - 100 = -4. Net change percentage = (-4/100) × 100 = -4% (a decrease of 4%).

Question 5

A company's revenue increased from ₹50 lakhs to ₹65 lakhs. What is the percentage increase in revenue?

Accepted Answer

Step 1: Original revenue = 50 lakhs. New revenue = 65 lakhs. Step 2: Increase = 65 - 50 = 15 lakhs. Step 3: Percentage increase = (Increase / Original) × 100 = (15 / 50) × 100 = 30%.

Question 6

A student scored 45% marks in an exam and failed by 36 marks. Another student scored 65% marks and passed by 24 marks. What is the passing percentage?

Accepted Answer

Step 1: Let total marks = x. First student: 0.45x = passing marks - 36. Second student: 0.65x = passing marks + 24. Step 2: Subtract equation 1 from equation 2: 0.65x - 0.45x = (passing marks + 24) - (passing marks - 36). Step 3: 0.20x = 60, so x = 300. Step 4: From equation 1: 0.45(300) = passing marks - 36, so 135 = passing marks - 36, passing marks = 171. Step 5: Passing% = (171/300) × 100 = 57%.

Question 7

A shopkeeper marks his goods 40% above the cost price. During a sale, he offers a discount of 25% on the marked price. What is his profit percentage?

Accepted Answer

Step 1: Let CP = 100. Marked Price = 100 + 40% of 100 = 140. Step 2: Discount = 25% of 140 = 35. Selling Price = 140 - 35 = 105. Step 3: Profit = 105 - 100 = 5. Profit% = (5/100) × 100 = 5%.

Question 8

In an examination, 35% of students failed in Mathematics, 28% failed in English, and 15% failed in both subjects. What percentage of students passed in both subjects?

Accepted Answer

Step 1: Students who failed in at least one subject = 35% + 28% - 15% = 48%. Step 2: Students who passed in both = 100% - 48% = 52%.

Question 9

A company's revenue increased from ₹50 lakhs to ₹65 lakhs. In the same period, expenses increased from ₹30 lakhs to ₹39 lakhs. By what percentage did the profit increase?

Accepted Answer

Step 1: Initial profit = 50 - 30 = 20 lakhs. Step 2: Final profit = 65 - 39 = 26 lakhs. Step 3: Profit increase = 26 - 20 = 6 lakhs. Step 4: Percentage increase = (6/20) × 100 = 30%.

Question 10

A shopkeeper marks up goods by 60% above cost price. He then offers a discount of 25% on the marked price during a sale. If the cost price of an item is ₹800, what is his profit percentage on the sale?

Accepted Answer

Step 1: Cost Price (CP) = ₹800. Step 2: Marked Price (MP) = 800 + 60% of 800 = 800 × 1.6 = ₹1280. Step 3: Selling Price (SP) after 25% discount = 1280 - 25% of 1280 = 1280 × 0.75 = ₹960. Step 4: Profit = SP - CP = 960 - 800 = ₹160. Step 5: Profit % = (160/800) × 100 = 20%.

Question 11

A company's revenue increased by 25% in Q1, decreased by 20% in Q2, and increased by 15% in Q3. If the revenue at the end of Q3 is ₹69,000, what was the revenue at the beginning of Q1?

Accepted Answer

Step 1: Let initial revenue = R. Step 2: After Q1 (25% increase): R × 1.25. Step 3: After Q2 (20% decrease): R × 1.25 × 0.8 = R × 1.0. Step 4: After Q3 (15% increase): R × 1.0 × 1.15 = R × 1.15. Step 5: R × 1.15 = 69,000. Step 6: R = 69,000 / 1.15 = 60,000. Therefore, initial revenue = ₹60,000.

Question 12

In an election, Candidate A received 45% of votes, Candidate B received 35% of votes, and Candidate C received the remaining votes. If Candidate A won by 2,000 votes over Candidate B, how many votes did Candidate C receive?

Accepted Answer

Step 1: Let total votes = V. Candidate A = 0.45V, Candidate B = 0.35V, Candidate C = 0.20V. Step 2: Difference between A and B = 0.45V - 0.35V = 0.10V = 2,000. Step 3: V = 2,000 / 0.10 = 20,000. Step 4: Candidate C = 0.20 × 20,000 = 4,000 votes.

Question 13

A student scored 65% in Math and 72% in English. If Math carries a weight of 40% and English carries a weight of 60%, what is the student's weighted average percentage?

Accepted Answer

Step 1: Weighted average = (Math score × Math weight) + (English score × English weight). Step 2: Weighted average = (65 × 0.40) + (72 × 0.60) = 26 + 43.2 = 69.2%. Therefore, weighted average = 69.2%.

SBI PO Percentage Word Problems

SBI PO Percentage Word Problems — Past Exam Questions

Percentage Word Problems— Rules & Concept

Key Points to Remember

Exam-Specific Tips

60-Second Revision — Percentage Word Problems