14 questions from actual SBI PO papers · all shown free · click option to reveal solution
Standard Deviation and Variance are measures that tell us how spread out data is from the average. Think of them as measuring 'how different' the numbers are from each other. CORE CONCEPT:
Imagine you have marks of 5 students: 10, 20, 30, 40, 50. All are spread out widely. Now imagine: 28, 29, 30, 31, 32. These are clustered tightly around 30. Both have the same average (30), but the spread is different. Variance and Standard Deviation measure this spread. Variance (σ²) = Average of squared differences from the mean
Standard Deviation (σ) = Square root of Variance KEY RULES:
1. Standard Deviation is always non-negative (≥0) 2. If all numbers are identical, SD = 0
3. Larger SD means more scattered data; smaller SD means data is clustered 4. Standard Deviation is preferred over Variance because it's in the same units as original data
SSC CGL typically asks: - Calculate SD or Variance from raw data - Compare spread of two datasets - Identify which dataset has more variation - Effect on SD when all values are multiplied or added by a constant SHORTCUT/TRICK: When values are multiplied by k: New SD = k × Original SD When values are added by c: New SD = Original SD (unchanged) This saves calculation time significantly.
Find mean = (2+4+6+8+10)/5 = 30/5 = 6
Find differences from mean: (2-6)=-4, (4-6)=-2, (6-6)=0, (8-6)=2, (10-6)=4
Square differences: 16, 4, 0, 4, 16
Variance = (16+4+0+4+16)/5 = 40/5 = 8
Standard Deviation = √8 = 2.83 (approximately)
Students forget to divide by n after summing squared differences. They calculate Σ(x-mean)² but stop there—this is NOT variance. You MUST divide by n.
Also, many confuse which measure to use; remember SD is more commonly reported in exams because it's interpretable.