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SSC GD Constable Relative Speed

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This page covers SSC GD Constable Relative Speed with complete concept notes, 12 graded practice MCQs, key points and exam-specific tips. Free to study.

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Concept Notes

Relative Speed— Rules & Concept

Core ConceptRead this first — the foundation of the topic
Core Concept

When two objects move, their relative speed depends on their direction. If they move towards each other, speeds add up. If they move in the same direction, speeds subtract. Imagine two trains - one coming towards you at 60 kmph while you travel at 40 kmph.

The relative speed is 100 kmph

Key Rules

For objects moving towards each other: Relative Speed = Speed1 + Speed2. For objects moving in same direction: Relative Speed = |Speed1 - Speed2|. For objects moving in opposite directions: Relative Speed = Speed1 + Speed2.

Formula BlockMemorise — at least one formula appears in every paper
• When approaching: Relative Speed = S1 + S2
• When separating/same direction: Relative Speed = |S1 - S2|
• Time to meet = Total Distance / Relative Speed
• Time to cross = (L1 + L2) / Relative Speed (for trains)
Exam PatternsWhat examiners ask — read before attempting PYQs

SSC loves asking about trains crossing each other, people walking towards/away from each other, and boats in rivers. Questions often involve calculating meeting time, crossing time, or finding individual speeds when relative speed is given.

ShortcutsUse these to save 30–60 seconds per question

#1: For train problems, always add train lengths when calculating crossing time. The faster train needs to cover the combined length of both trains to completely cross.

Worked ExampleSolve this step-by-step before moving on
1
Step 1

Convert speeds to m/s: 54 kmph = 54 × 5/18 = 15 m/s, 36 kmph = 36 × 5/18 = 10 m/s

2
Step 2

Relative speed = 15 + 10 = 25 m/s (opposite directions)

3
Step 3

Combined length = 120 + 80 = 200m

4
Step 4

Time = Distance/Speed = 200/25 = 8 seconds Shortcut Trick #2: Speed conversion hack: kmph to m/s, multiply by 5/18. m/s to kmph, multiply by 18/5. Remember: 5/18 ≈ 0.278, 18/5 = 3.6 Worked Example 2: A man walks at 5 kmph. A car travels at 45 kmph in same direction. If car is initially 2 km behind, when will it catch up?

1
Step 1

Relative speed = 45 - 5 = 40 kmph (same direction, so subtract)

2
Step 2

Distance to cover = 2 km

3
Step 3

Time = Distance/Relative Speed = 2/40 = 0.05 hours = 3 minutes Shortcut Trick #3: For meeting point problems, use the ratio method. If two objects start from opposite ends with speeds S1 and S2, they meet at a point dividing the distance in ratio S1:S2. Most

Exam TrapsCommon mistakes students make — avoid these

Students forget to add lengths when trains cross each other. They only use train speeds but ignore that crossing means one train must travel its own length plus the other train's length. Always remember: crossing distance = sum of lengths, not just individual train length. Another frequent error is wrong direction calculation.

When objects move towards each other, always add speeds. When in same direction, always subtract. Never confuse these basic rules, as they form the foundation of every relative speed problem in SSC CGL.

Key Points to Remember

  • Relative speed = S1 + S2 when objects move towards each other
  • Relative speed = |S1 - S2| when objects move in same direction
  • For train crossing: Time = (L1 + L2) / Relative Speed
  • Speed conversion: kmph to m/s multiply by 5/18
  • Meeting time = Total distance / Relative speed
  • When trains cross, always add both train lengths to find distance
  • Objects starting from opposite ends meet at distance ratio S1:S2
  • In river problems: Downstream speed = Boat speed + River speed
  • Upstream speed = Boat speed - River speed
  • Relative speed is always positive, use absolute value for same direction

Exam-Specific Tips

  • Speed conversion factor from kmph to m/s is exactly 5/18
  • Speed conversion factor from m/s to kmph is exactly 18/5 or 3.6
  • When two trains cross each other, distance = sum of both train lengths
  • For circular track problems, relative speed determines lap completion time
  • Meeting point divides total distance in ratio of individual speeds
  • In boat problems, still water speed = (Downstream + Upstream)/2
  • River current speed = (Downstream - Upstream)/2
  • Two objects starting together separate at their relative speed rate
Practice MCQs

Relative Speed — Practice Questions

12graded MCQs · easy to hard · full solution & trap analysis

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Practice 1easy

Two trains are moving towards each other on parallel tracks. Train A travels at 60 km/h and Train B travels at 40 km/h. If they are currently 500 km apart, how long will it take for them to meet?

Practice 2easy

A person walks at 5 km/h and a bus travels at 45 km/h in the same direction. If the bus is 80 km behind the person, how long will it take for the bus to catch up?

Practice 3easy

Two runners start from opposite ends of a 400-meter track and run towards each other. Runner X runs at 8 m/s and Runner Y at 12 m/s. In how many seconds will they meet?

Practice 4easy

A boat travels upstream at 12 km/h and downstream at 20 km/h. What is the speed of the current?

Practice 5easy

Two cyclists start from the same point and travel in opposite directions. Cyclist A travels at 15 km/h and Cyclist B at 25 km/h. After how many hours will they be 160 km apart?

Practice 6easy

A car and a motorcycle are travelling in the same direction on a highway. The car travels at 80 km/h and the motorcycle at 50 km/h. If the motorcycle is currently 90 km ahead of the car, how long will it take for the car to catch up?

Practice 7medium

Two trains are moving towards each other on parallel tracks. Train A travels at 60 km/h and Train B travels at 40 km/h. If they are initially 500 km apart, in how many hours will they meet?

Practice 8medium

A boat travels upstream at 12 km/h and downstream at 20 km/h. What is the speed of the boat in still water?

Practice 9medium

A car and a motorcycle start from the same point and travel in the same direction. The car travels at 80 km/h and the motorcycle at 50 km/h. After how many hours will the car be 90 km ahead of the motorcycle?

Practice 10hard

Two trains A and B start simultaneously from stations X and Y respectively, which are 480 km apart. Train A travels towards Y at 60 km/h, while train B travels towards X at 40 km/h. After how many hours will they meet, and at what distance from station X?

Practice 11hard

A boat travels 120 km downstream in 4 hours and the same distance upstream in 6 hours. A swimmer swims at the same speed as the boat's speed in still water. How long will the swimmer take to cover 45 km in still water?

Practice 12hard

Two runners, P and Q, run on a circular track of length 400 metres. P runs at 8 m/s and Q at 6 m/s, both starting from the same point in the same direction. After how many seconds will P lap Q (i.e., be exactly one full lap ahead)?

60-Second Revision — Relative Speed

  • Formula: Towards each other = S1 + S2, Same direction = |S1 - S2|
  • Remember: Train crossing always needs combined length of both trains
  • Trap: Never forget to convert units - kmph to m/s multiply by 5/18
  • Quick check: Relative speed should make logical sense with given scenario
  • Meeting time = Total distance divided by relative speed
  • Boat speed formulas: Still water = (Down+Up)/2, Current = (Down-Up)/2
  • Always use absolute value when calculating same direction relative speed
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