Question 1

A shopkeeper marks his goods at 40% above the cost price. If he gives a discount of 10% on the marked price, what is his profit percentage?

Accepted Answer

Step 1: Let cost price = 100. Marked price = 100 + 40% of 100 = 140. Step 2: Discount = 10% of 140 = 14. Selling price = 140 - 14 = 126. Step 3: Profit = 126 - 100 = 26. Profit percentage = (26/100) × 100 = 26%.

Question 2

In an election, candidate A received 55% of the votes and candidate B received the remaining votes. If the total number of votes cast was 8000, how many more votes did A receive than B?

Accepted Answer

Step 1: Votes for A = 55% of 8000 = 0.55 × 8000 = 4400. Step 2: Votes for B = 45% of 8000 = 0.45 × 8000 = 3600. Step 3: Difference = 4400 - 3600 = 800.

Question 3

A student scored 72% in English and 88% in Mathematics. If the maximum marks in each subject is 150, what is the total percentage of marks obtained?

Accepted Answer

Step 1: Marks in English = 72% of 150 = 0.72 × 150 = 108. Step 2: Marks in Mathematics = 88% of 150 = 0.88 × 150 = 132. Step 3: Total marks obtained = 108 + 132 = 240. Step 4: Total maximum marks = 150 + 150 = 300. Step 5: Total percentage = (240/300) × 100 = 80%.

Question 4

A company's revenue increased from ₹40 lakhs to ₹50 lakhs. What is the percentage increase in revenue?

Accepted Answer

Step 1: Increase in revenue = 50 - 40 = 10 lakhs. Step 2: Percentage increase = (Increase / Original) × 100 = (10 / 40) × 100 = 25%.

Question 5

A student needs to score 40% to pass an exam. If the maximum marks is 250, how many marks must the student score to pass?

Accepted Answer

Step 1: Passing marks = 40% of 250 = 0.40 × 250 = 100. Therefore, the student must score at least 100 marks to pass.

Question 6

The price of a commodity increased by 20% last year and decreased by 10% this year. If the original price was ₹500, what is the current price?

Accepted Answer

Step 1: Price after 20% increase = 500 + 20% of 500 = 500 + 100 = 600. Step 2: Price after 10% decrease = 600 - 10% of 600 = 600 - 60 = 540. Therefore, current price is ₹540.

Question 7

The price of a commodity increases by 20% in January and then decreases by 15% in February. In March, it increases by 10%. If the final price in March is ₹1,122, what was the original price?

Accepted Answer

Step 1: Let original price = P. After January (20% increase): P × 1.20. Step 2: After February (15% decrease): P × 1.20 × 0.85. Step 3: After March (10% increase): P × 1.20 × 0.85 × 1.10 = P × 1.122. Step 4: P × 1.122 = 1,122. P = 1,000.

Question 8

In an examination, 35% of students failed in Hindi, 28% failed in English, and 20% failed in both subjects. What percentage of students passed in both subjects?

Accepted Answer

Step 1: Let total students = 100. Failed in Hindi = 35, Failed in English = 28, Failed in both = 20. Step 2: Using set theory: Failed in at least one subject = 35 + 28 - 20 = 43. Step 3: Passed in both subjects = 100 - 43 = 57%.

Question 9

A student scored 45% marks in an exam and failed by 36 marks. Another student scored 65% marks and passed by 24 marks. What is the passing percentage?

Accepted Answer

Step 1: Let total marks = M and passing marks = P. From first student: 0.45M = P - 36. From second student: 0.65M = P + 24. Step 2: Subtracting: 0.65M - 0.45M = (P + 24) - (P - 36). 0.20M = 60. M = 300. Step 3: From first equation: 0.45(300) = P - 36. 135 = P - 36. P = 171. Step 4: Passing percentage = (171/300) × 100 = 57%.

Question 10

A shopkeeper marks his goods at 60% above the cost price. He then offers a discount of 25% on the marked price. What is his profit percentage?

Accepted Answer

Step 1: Let cost price = 100. Marked price = 100 + 60% of 100 = 160. Step 2: Discount = 25% of 160 = 40. Selling price = 160 - 40 = 120. Step 3: Profit = 120 - 100 = 20. Profit percentage = (20/100) × 100 = 20%.

Question 11

A town's population increases by 25% in the first year. In the second year, it decreases by 20%. In the third year, it increases by 10%. If the population after three years is 33,000, what was the initial population?

Accepted Answer

Step 1: Let initial population = P. After year 1 (25% increase): P × 1.25. Step 2: After year 2 (20% decrease): P × 1.25 × 0.80 = P × 1.00. Step 3: After year 3 (10% increase): P × 1.00 × 1.10 = P × 1.10. Step 4: P × 1.10 = 33,000. P = 30,000.

Question 12

A person spends 25% of his income on rent, 30% on food, and 15% on utilities. He saves the remaining amount. If he saves ₹18,000 per month, what is his total monthly income?

Accepted Answer

Step 1: Total spending percentage = 25% + 30% + 15% = 70%. Step 2: Savings percentage = 100% - 70% = 30%. Step 3: If 30% of income = ₹18,000, then income = 18,000 / 0.30 = ₹60,000.

Question 13

In a college, 40% of students are in Science, 35% are in Commerce, and the remaining are in Arts. If 20% of Science students and 30% of Commerce students pass an entrance exam, what percentage of the total student population passed the exam?

Accepted Answer

Step 1: Let total students = 100. Science = 40, Commerce = 35, Arts = 25. Step 2: Science students who passed = 20% of 40 = 8. Step 3: Commerce students who passed = 30% of 35 = 10.5. Step 4: Total passed = 8 + 10.5 = 18.5. Step 5: Percentage of total = (18.5/100) × 100 = 18.5%.

Question 14

A shopkeeper buys goods at ₹100 per unit. He marks them up by 50% and offers a discount of 10% on the marked price. Later, he offers an additional 5% discount on the already-discounted price. What is his overall profit percentage?

Accepted Answer

Step 1: Cost Price = ₹100. Marked Price = 100 × 1.50 = ₹150. Step 2: After first discount (10%): Price = 150 × 0.90 = ₹135. Step 3: After second discount (5%): Selling Price = 135 × 0.95 = ₹128.25. Step 4: Profit = 128.25 - 100 = ₹28.25. Step 5: Profit% = (28.25 / 100) × 100 = 28.25%.

IBPS RRB PO Percentage Word Problems

IBPS RRB PO Percentage Word Problems — Past Exam Questions

Percentage Word Problems— Rules & Concept

Key Points to Remember

Exam-Specific Tips

60-Second Revision — Percentage Word Problems