Question 1

A bus travels from City A to City B at a speed of 60 km/h. On the return journey, it travels at 40 km/h. If the distance between the two cities is 120 km, what is the average speed of the bus for the entire journey (both ways)?

Accepted Answer

Step 1: Calculate time taken from A to B: Time = Distance/Speed = 120/60 = 2 hours. Step 2: Calculate time taken from B to A: Time = 120/40 = 3 hours. Step 3: Total distance covered = 120 + 120 = 240 km. Step 4: Total time taken = 2 + 3 = 5 hours. Step 5: Average speed = Total distance/Total time = 240/5 = 48 km/h. Therefore, the average speed is 48 km/h.

Question 2

A cyclist covers 180 metres in 9 seconds. What is his speed in m/s?

Accepted Answer

Step 1: Apply Speed = Distance ÷ Time. Step 2: Speed = 180 ÷ 9 = 20 m/s. Therefore, the cyclist's speed is 20 m/s.

Question 3

A train travels at 72 km/h. How much distance will it cover in 5 hours?

Accepted Answer

Step 1: Use the formula Distance = Speed × Time. Step 2: Distance = 72 × 5 = 360 km. Therefore, the train covers 360 km in 5 hours.

Question 4

A bus covers 150 km in 3 hours. How much time will it take to cover 250 km at the same speed?

Accepted Answer

Step 1: Find the speed using Speed = Distance ÷ Time = 150 ÷ 3 = 50 km/h. Step 2: Find time using Time = Distance ÷ Speed = 250 ÷ 50 = 5 hours. Therefore, it takes 5 hours to cover 250 km.

Question 5

A man walks at 4 km/h. How long will it take him to walk 12 km?

Accepted Answer

Step 1: Use the formula Time = Distance ÷ Speed. Step 2: Time = 12 ÷ 4 = 3 hours. Therefore, it takes 3 hours to walk 12 km.

Question 6

A cyclist covers 75 km in 5 hours. How long will it take him to cover 120 km at the same speed?

Accepted Answer

Step 1: Calculate speed using Speed = Distance ÷ Time. Speed = 75 ÷ 5 = 15 km/h. Step 2: Calculate time for 120 km using Time = Distance ÷ Speed. Time = 120 ÷ 15 = 8 hours.

Question 7

A train travels at 90 km/h. How far will it travel in 20 minutes?

Accepted Answer

Step 1: Convert time to hours. 20 minutes = 20/60 hours = 1/3 hours. Step 2: Calculate distance using Distance = Speed × Time. Distance = 90 × (1/3) = 30 km.

Question 8

A runner covers 400 metres in 50 seconds. What is his speed in m/s?

Accepted Answer

Step 1: Apply Speed = Distance ÷ Time. Step 2: Speed = 400 ÷ 50 = 8 m/s. Therefore, the runner's speed is 8 m/s.

Question 9

A car travels 240 km in 4 hours. What is its average speed in km/h?

Accepted Answer

Step 1: Use the formula Speed = Distance ÷ Time. Step 2: Speed = 240 ÷ 4 = 60 km/h. Therefore, the average speed is 60 km/h.

Question 10

A person walks at 4 km/h and covers a certain distance in 3 hours. If he walks at 6 km/h, how much time will he take to cover the same distance?

Accepted Answer

Step 1: Calculate the distance using Distance = Speed × Time. Distance = 4 × 3 = 12 km. Step 2: Calculate new time using Time = Distance ÷ Speed. Time = 12 ÷ 6 = 2 hours.

Question 11

A car travels from City A to City B at 50 km/h and returns at 75 km/h. If the total journey takes 10 hours, what is the distance between the two cities?

Accepted Answer

Step 1: Let distance = d km. Step 2: Time for A to B = d/50 hours; Time for B to A = d/75 hours. Step 3: Total time: d/50 + d/75 = 10. Step 4: LCM(50,75) = 150. So (3d + 2d)/150 = 10 → 5d/150 = 10 → d/30 = 10 → d = 300 km.

Question 12

A cyclist covers 180 km in 5 hours. If he reduces his speed by 25%, how much distance will he cover in 8 hours at the new speed?

Accepted Answer

Step 1: Original speed = 180 ÷ 5 = 36 km/h. Step 2: Speed reduced by 25%: New speed = 36 × 0.75 = 27 km/h. Step 3: Distance in 8 hours = 27 × 8 = 216 km.

Question 13

Two runners start from the same point. Runner A runs at 12 km/h and Runner B runs at 8 km/h in the same direction. After how many hours will Runner A be 20 km ahead of Runner B?

Accepted Answer

Step 1: Relative speed = 12 - 8 = 4 km/h (since they run in the same direction). Step 2: Time = Distance ÷ Relative Speed = 20 ÷ 4 = 5 hours.

Question 14

A boat travels 48 km downstream in 3 hours and 48 km upstream in 6 hours. What is the speed of the boat in still water?

Accepted Answer

Step 1: Downstream speed = 48 ÷ 3 = 16 km/h. Step 2: Upstream speed = 48 ÷ 6 = 8 km/h. Step 3: Speed of boat in still water = (Downstream speed + Upstream speed) ÷ 2 = (16 + 8) ÷ 2 = 12 km/h.

Question 15

A person walks from point P to point Q at 4 km/h and returns from Q to P at 6 km/h. If the total time taken is 5 hours, what is the distance between P and Q?

Accepted Answer

Step 1: Let distance = d km. Step 2: Time from P to Q = d/4 hours; Time from Q to P = d/6 hours. Step 3: Total time: d/4 + d/6 = 5. Step 4: LCM(4,6) = 12. So (3d + 2d)/12 = 5 → 5d/12 = 5 → d = 12 km.

Question 16

A train travels 240 km in 4 hours at constant speed. If it needs to cover 360 km at the same speed, how much additional time (in hours) will it require beyond the first 4 hours?

Accepted Answer

Step 1: Calculate speed from first journey: Speed = Distance ÷ Time = 240 ÷ 4 = 60 km/h. Step 2: Calculate time for 360 km: Time = 360 ÷ 60 = 6 hours. Step 3: Additional time = 6 - 4 = 2 hours.

Question 17

Two runners start from the same point. Runner A runs at 8 m/s and Runner B runs at 6 m/s in the same direction. After how many seconds will Runner A be 100 metres ahead of Runner B?

Accepted Answer

Step 1: Find relative speed = Speed of A - Speed of B = 8 - 6 = 2 m/s. Step 2: Runner A gains 2 metres on Runner B every second. Step 3: To gain 100 metres: Time = Distance ÷ Relative Speed = 100 ÷ 2 = 50 seconds.

Question 18

A car travels from City P to City Q at 60 km/h and returns from Q to P at 40 km/h. If the distance between P and Q is 120 km, what is the average speed for the entire journey?

Accepted Answer

Step 1: Total distance = 120 + 120 = 240 km. Step 2: Time from P to Q = 120 ÷ 60 = 2 hours. Step 3: Time from Q to P = 120 ÷ 40 = 3 hours. Step 4: Total time = 2 + 3 = 5 hours. Step 5: Average speed = Total distance ÷ Total time = 240 ÷ 5 = 48 km/h.

Question 19

Two cyclists start from the same point and travel in opposite directions on a circular track of circumference 1200 m. Cyclist A travels at 8 m/s and Cyclist B travels at 7 m/s. After how many seconds will they meet for the second time?

Accepted Answer

Step 1: When travelling in opposite directions on a circular track, their relative speed = 8 + 7 = 15 m/s. Step 2: For the first meeting, they together cover the circumference once: Time for first meeting = 1200 ÷ 15 = 80 seconds. Step 3: For the second meeting, they together cover the circumference twice: Time for second meeting = (2 × 1200) ÷ 15 = 2400 ÷ 15 = 160 seconds.

Question 20

A person walks from Point X to Point Y at 4 km/h and returns from Y to X at 6 km/h. The total time taken for the round trip is 5 hours. What is the distance between X and Y in km?

Accepted Answer

Step 1: Let distance between X and Y = d km. Step 2: Time from X to Y = d/4 hours. Step 3: Time from Y to X = d/6 hours. Step 4: Total time = d/4 + d/6 = 5 hours. Step 5: Finding common denominator: (3d + 2d)/12 = 5, so 5d/12 = 5. Step 6: 5d = 60, therefore d = 12 km.

Question 21

A train travels 240 km in 4 hours. If it increases its speed by 20%, how much time will it take to cover 432 km at the new speed?

Accepted Answer

Step 1: Original speed = 240 ÷ 4 = 60 km/h. Step 2: New speed = 60 × 1.20 = 72 km/h. Step 3: Time = Distance ÷ Speed = 432 ÷ 72 = 6 hours.

SSC CHSL Speed Distance Time

SSC CHSL Speed Distance Time — Past Exam Questions

Speed Distance Time— Rules & Concept

Key Points to Remember

Exam-Specific Tips

Speed Distance Time — Practice Questions

60-Second Revision — Speed Distance Time