Question 1

A runner completes 800 metres in 160 seconds. What is the runner's speed in m/s?

Accepted Answer

Step 1: Apply Speed = Distance ÷ Time. Step 2: Speed = 800 ÷ 160 = 5 m/s. Therefore, the answer is 5 m/s.

Question 2

A bus covers 360 km in 6 hours. If it travels at the same speed, how much distance will it cover in 9 hours?

Accepted Answer

Step 1: Find speed = 360 ÷ 6 = 60 km/h. Step 2: Distance = Speed × Time = 60 × 9 = 540 km. Therefore, the answer is 540 km.

Question 3

A cyclist covers 180 metres in 9 seconds. What is the cyclist's speed in m/s?

Accepted Answer

Step 1: Apply Speed = Distance ÷ Time. Step 2: Speed = 180 ÷ 9 = 20 m/s. Therefore, the answer is 20 m/s.

Question 4

A car travels 240 km in 4 hours. What is its speed in km/h?

Accepted Answer

Step 1: Use the formula Speed = Distance ÷ Time. Step 2: Speed = 240 ÷ 4 = 60 km/h. Therefore, the answer is 60 km/h.

Question 5

A train travels at 72 km/h. How far will it travel in 5 hours?

Accepted Answer

Step 1: Use the formula Distance = Speed × Time. Step 2: Distance = 72 × 5 = 360 km. Therefore, the answer is 360 km.

Question 6

A person walks 150 metres in 30 seconds. How long will it take to walk 450 metres at the same speed?

Accepted Answer

Step 1: Find speed = 150 ÷ 30 = 5 m/s. Step 2: Use Time = Distance ÷ Speed. Step 3: Time = 450 ÷ 5 = 90 seconds. Therefore, the answer is 90 seconds.

Question 7

A boat travels 48 km downstream in 3 hours and 48 km upstream in 6 hours. What is the speed of the boat in still water?

Accepted Answer

Step 1: Downstream speed = 48 ÷ 3 = 16 km/h. Step 2: Upstream speed = 48 ÷ 6 = 8 km/h. Step 3: Speed of boat in still water = (Downstream speed + Upstream speed) ÷ 2 = (16 + 8) ÷ 2 = 12 km/h.

Question 8

A cyclist covers 180 km in 5 hours. A car covers the same distance in 3 hours. What is the ratio of their speeds?

Accepted Answer

Step 1: Cyclist's speed = 180 ÷ 5 = 36 km/h. Step 2: Car's speed = 180 ÷ 3 = 60 km/h. Step 3: Ratio = 36 : 60 = 3 : 5.

Question 9

Two trains start from the same station at the same time. Train A travels at 60 km/h and Train B travels at 80 km/h in the same direction. After how many hours will Train B be 100 km ahead of Train A?

Accepted Answer

Step 1: Relative speed = 80 - 60 = 20 km/h (since both travel in same direction). Step 2: Time = Distance ÷ Relative speed = 100 ÷ 20 = 5 hours.

Question 10

A person travels from City P to City Q, a distance of 300 km. He covers the first 150 km at 50 km/h and the remaining 150 km at 75 km/h. What is his average speed for the entire journey?

Accepted Answer

Step 1: Time for first 150 km = 150 ÷ 50 = 3 hours. Step 2: Time for remaining 150 km = 150 ÷ 75 = 2 hours. Step 3: Total distance = 300 km. Step 4: Total time = 3 + 2 = 5 hours. Step 5: Average speed = 300 ÷ 5 = 60 km/h.

Question 11

Two cyclists start simultaneously from the same point and travel in the same direction. Cyclist A travels at 24 km/h and Cyclist B travels at 32 km/h. After how much time will Cyclist B be exactly 40 km ahead of Cyclist A?

Accepted Answer

Step 1: Relative speed = 32 - 24 = 8 km/h (B is faster, so gains 8 km every hour). Step 2: To gain 40 km at a relative speed of 8 km/h: Time = 40 ÷ 8 = 5 hours. Step 3: Verification: In 5 hours, A travels 24 × 5 = 120 km; B travels 32 × 5 = 160 km. Difference = 160 - 120 = 40 km. ✓

Question 12

A boat takes 6 hours to travel 120 km downstream and 8 hours to travel the same distance upstream. If the boat's speed in still water is b km/h and the current's speed is c km/h, what is the value of b?

Accepted Answer

Step 1: Downstream speed = 120 ÷ 6 = 20 km/h. So b + c = 20. Step 2: Upstream speed = 120 ÷ 8 = 15 km/h. So b - c = 15. Step 3: Add both equations: (b + c) + (b - c) = 20 + 15 → 2b = 35 → b = 17.5 km/h.

Question 13

A person walks from Point P to Point Q at 4 km/h and returns from Q to P at 6 km/h. The total time taken for the round trip is 5 hours. What is the distance between P and Q?

Accepted Answer

Step 1: Let distance = d km. Step 2: Time from P to Q at 4 km/h = d/4 hours. Step 3: Time from Q to P at 6 km/h = d/6 hours. Step 4: Total time = d/4 + d/6 = 5. Step 5: Find LCM of 4 and 6 = 12. So (3d + 2d)/12 = 5 → 5d/12 = 5 → d = 12 km.

Question 14

A car travels from City X to City Y at a speed of 60 km/h. On the return journey, due to traffic, it travels at 40 km/h. If the total time taken for the round trip is 10 hours, what is the distance between City X and City Y?

Accepted Answer

Step 1: Let distance = d km. Step 2: Time from X to Y at 60 km/h = d/60 hours. Step 3: Time from Y to X at 40 km/h = d/40 hours. Step 4: Total time = d/60 + d/40 = 10. Step 5: Find LCM of 60 and 40 = 120. So (2d + 3d)/120 = 10 → 5d/120 = 10 → d/24 = 10 → d = 240 km.

SSC MTS Speed Distance Time

Speed Distance Time— Rules & Concept

Key Points to Remember

Exam-Specific Tips

Speed Distance Time — Practice Questions

60-Second Revision — Speed Distance Time